Why Does the Minus Sign Appear in Momentum Transfer Equation?

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SUMMARY

The discussion centers on the appearance of the minus sign in the momentum transfer equation, specifically in the context of the equation \((p_1 - p_3)^2=-(\mathbf p_1 - \mathbf p_3)^2\). The four-momentum vectors are defined as \(p_1=(E/c,\mathbf p_1)\) and \(p_3=(E/c,\mathbf p_3)\) for the incident and scattered electrons, respectively. The user initially struggled with the derivation but ultimately resolved the confusion regarding the minus sign through self-analysis.

PREREQUISITES
  • Understanding of four-momentum in special relativity
  • Familiarity with vector notation and operations
  • Knowledge of energy-momentum relations
  • Basic algebraic manipulation skills
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  • Study the derivation of four-momentum in special relativity
  • Learn about the implications of negative signs in physical equations
  • Explore the concept of momentum transfer in particle physics
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Students of physics, particularly those focusing on particle physics and special relativity, as well as educators seeking to clarify concepts related to momentum transfer equations.

Muh. Fauzi M.
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Homework Statement


This is just a simple proof of substitution, but after one day struggle, I still can't get where that minus sign appear.

Homework Equations


Here is the equation:
$$ (p_1 - p_3)^2=-(\mathbf p_1 - \mathbf p_3)^2$$
where ##p_1=(E/c,\mathbf p_1)## and ##p_3=(E/c, \mathbf p_3)## is four-momentum of incident and scattered electron respectively, with stationary target.

The Attempt at a Solution


Here is my doodling:
$$
(p_1 - p_3)^2=(E/c+\mathbf p_1-E/c-\mathbf p_3)^2=(\mathbf p_1 - \mathbf p_3)^2.
$$
Which step that I miss?
 
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ah, I've got it. solved by myself.
 

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