Why does the slope of a PT Graph equal the VT graph?

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Can someone please explain this to me (please see title)? I understand how to compute it but why is this so?

Thanks
 
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You mean momentum-time graph and velocity-time graph?
 
or is it the pressure-temperature and volume-temperature graph for ideal gases?
 
I mean Position-Time and Velocity-Time.
 
What does slope mean?

Slope = [tex]\frac{\Delta Y}{\Delta X}[/tex]

What is your Y-axis? position (meters)
What is your X-axis? time (seconds)

Therefore,

Slope = position/time = meters/seconds = velocity

Velocity is the change of rate of change of position per unit time.