Why does this function have a unique shape?

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Homework Help Overview

The discussion revolves around understanding the unique shape of the function f(x) = abs(x + 4) + abs(3 - x). The original poster expresses confusion about the graph produced by an online tool and seeks clarification on the function's characteristics.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants suggest creating a table of values for the function over a specified range to better understand its behavior. Others propose rewriting the function as a piecewise formula to analyze the absolute values involved.

Discussion Status

The discussion is active, with participants exploring different methods to analyze the function's shape. Suggestions for breaking down the function into simpler components have been made, indicating a productive direction without reaching a consensus.

Contextual Notes

There is an emphasis on understanding the function's behavior through piecewise analysis, and participants are encouraged to consider different intervals for x to clarify the absolute value expressions.

abdo799
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basically, i am given a function and told to sketch it. f(x)=abs(x+4) + abs(3-x)
i didnt know how to do it, so i used this site ( http://rechneronline.de/function-graphs/ )
it gave this graph with a really weird shape , can anyone explain it??
i tried to google it to find the answer, but i didnt even know what to type and search
 
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Surely, if no other way, you could just make a table of values for x from say -6 to 6. How hard can that be? Try it.
 
LCKurtz said:
Surely, if no other way, you could just make a table of values for x from say -6 to 6. How hard can that be? Try it.

i did the sketch , i need to know why it has this shape
 
abdo799 said:
i did the sketch , i need to know why it has this shape

Try writing your function as a muti-piece formula. For example, if ##x < -4## what would ##|x+4|## and ##|3-x|## be without the absolute value signs. Then try ##-4<x<3## and so on. Remember ##|x| = x,~x>0## and ##|x| = -x,~x<0##.
 

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