Why does this function make it easy to prove continuity with sequences?

[WWGD]

I thought the goal was showing continuity using $[x_n \rightarrow x ]\rightarrow [f(x_n) \rightarrow x]$

 

[mcastillo356]

It's as simple and basic as that.

Furthermore, it's the real thing

A simpler approach was simply to note that:
$$|f(x) - f(0)| = |f(x)| \le |x|$$

Definitively, compañero.

I thought the goal was showing continuity using $[x_n \rightarrow x ]\rightarrow [f(x_n) \rightarrow x]$

Yes.

This...

This... Was as simple as @PeroK knew; as hard as I turned it.
A thousand thanks, milesker, bihotzez.
HNY, PF!

 

[Mark44]

A thousand thanks, milesker, bihotzez.

Are the last two words Basque? I definitely don't recognize them as Spanish.

 

[WWGD]

J

Are the last two words Basque? I definitely don't recognize them as Spanish.

Just basqueing in the glory of Spanish regional languages.

 

[mcastillo356]

In Basque, yes, "a thousand thanks, from the heart".
PD @FactChecker, I feel I should have written a few more about #30, but I've plunged headlong into the next chapter, integration.
Love, greetings, PF.