Why does this MOSFET turn on initially in saturation?

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The discussion centers on the behavior of a MOSFET as it transitions from cutoff to saturation. It highlights that as the input voltage (Vin) approaches the threshold voltage (Vth), the MOSFET (M1) begins to conduct, drawing current from the drain resistor (Rd) and lowering the output voltage (Vout). The condition for saturation is explained through the relationship between Vout, Vin, and Vth, indicating that Vout must exceed Vin minus Vth for saturation to occur. The importance of analyzing characteristic curves and load lines is emphasized to understand the MOSFET's operation during this transition. Ultimately, the discussion seeks clarity on how these principles confirm that the MOSFET turns on in saturation.
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Homework Statement


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Razavi's book (Analgoue CMOS Integrated Circuits) says that that "as Vin approaches Vth, M1 begins to turn on, drawing current from Rd and lowering Vout. Transistor M1 turns on in saturation regardless of the values of Vdd and Rd."

Why is that? I mean that the condition for saturation is (assuming Vgs > Vth) is:
For Saturation:
$$V_{DS} > V_{GS} - V_{TH} $$
Simplifies to:
$$V_{out}>V_{in} - V_{TH}$$

How does that prove it will turn on in saturation?

Homework Equations

The Attempt at a Solution

 

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Personally, I look at the characteristic curves rather than the formulae, but either way is ok.

When the mosfet is cut off, what is the output voltage?
And the input voltage?
Now, as the input voltage rises, at what level does the mosfet start to turn on?
What is the output voltage just before or just as the mosfet starts to turn on?
Are your inequalities satisfied?

Otherwise, on a ID vs VDS graph of characteristic curves, draw in a load line for RD (any nominal value will do.) The output voltage will lie on the load line. Look at the point where it is just switching on. What region must it be in?
 

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