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Why doesn't Graphene have a band gap?

  1. Sep 28, 2014 #1
    Is there any simple justification about graphene having no band gap? How bout its linear E-K? Why bilayer graphene has a quadratic E-K and electric field can open a band gap there?

    I do not completely understand the broken symmetry argument? Also Why MoS2 which has similar structure, do not have similar properties?

    I know that we can create the Hamiltonian, plot the band-structure numerically and answer these questions. But I want to know if we can use some simple quantum theory arguments (like perturbation theory, or Fermi golden rule) or symmetry facts to get a qualitative answer for all of these questions.
     
  2. jcsd
  3. Sep 29, 2014 #2

    DrDu

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    I don't know whether you are familiar with x-ray structure analysis. There you encounter a similar phenomenon: Systematic absences. Usually, the splitting of two bands near the Brillouin zone boundary is due to strong reflection of the Bloch waves, or, what amounts to the same, a strong mixing of counter propagating waves, leading to a sin and a cos wave with different energy. However in graphene, these reflections are absent along special directions as you have two reflecting lines of atoms which are not spaced by a lattice vector, but only half of it. You easily see this as follows: Fill the centers of the hexagons with additional C atoms: Apparently you get a primitive closest packed 2d crystal with smaller unit cell. Some of these lattice lines are also present in graphene with equal density of C atoms on them, though they are no longer connected by a lattice vector.
     
  4. Sep 29, 2014 #3
    Thanks DrDu. Do you have a reference so I can take a look into the details? Also do you have idea about the other questions?
     
  5. Sep 29, 2014 #4

    DrDu

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    No, I have no literature at hand. You can also see it like this: in graphene, each C atom has 3 nearest neighbours. At the conical point, the first C atom is in phase, 1, the second is ##\exp(\pm 2\pi/3)## out of phase and the third one ##\exp(\mp2\pi/3)## out of phase, so that the interaction of a c atom with it's nearest neighbours vanishes. As there are two possible signs of the phase factor, you see that there are two conical points in K space. Hence the two sub lattices consisting of all atoms being next-nearest neighbours don't interact at the conical points and are energetically degenerate, as the atoms are identical. In other substances, like BN, the sub lattices are formed from different elements (B and N, respectively), which have different energies, so there is a band gap.
    In MoS2 and graphene double layers, similar arguments as in BN should apply.
     
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