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- Thread starter SMA_01
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HallsofIvy

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The image of G in what function?

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What are you allowed to use? If you know that the image of a homomorphism is a subgroup and you know the order of a subgroup divides the order of the group, you're done. Otherwise you'll have to prove one or both of those facts from first principles.

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Yes of course. Sorry, little brain hiccup at my end. Nevermind what I wrote. You're right, if the homomorphism's not onto then the image will be a proper subset of G'.

(edit) Ok I owe you a better hint. Do you know the first isomorphism theorem?

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