blue_phoenix
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1. Bond's usual gun of choice in every movie is a Walther PPK (except when he can get his hands on a machine gun
which blows up more guys). A bullet like this has a mass of around 15g and leaves the gun at 288m/s. Calculate the
kinetic energy in a bullet like this.
2.Aside from shooting bad guys, Bond has a lot off success with, ummm, the ladies. Imagine he is resting in bed one morning
1 m off the ground and that his mass is 63.5 kg. What is his potential energy relative to the ground when he in bed?
3. Do answers from (1) and (2) surprise you? Why is a bullet more damaging than falling out of bed from a height of 1 m?
2. I think i have to use the formula of kinetic energy. Kinetic energy = (mv^2)2 and gravitational potential energy = mgh
sorry i can't use the codes properly so i wrote it this way
3. For number 1 i did
E_k=(mv^2)/2
= (0.015)(288^2)/2
=622.05 J
=6.22 x 10^2 J
so the kinetic energy is 6.22 x 10^2 J
Is this approximation correct since the question has 3 sig figs?
for number 2 i did
Eg=mgh
=63.5 x 9.80 x 1
=622.3 J
=6.22 x 10^2 J
so the gravitational potential enegry is 6.22 x 10^2 J
Is it also appropriate?
for number 3 i wrote
A bullet is more damaging than falling out of bed from height of 1 m because a bullet with its smaller surface area causes more impact on the small area thus creating more damage where is the pressure by falling one meter is spread through the whole body enabling the body to dissipate the damage and get less hurt.
Is it accurate?
which blows up more guys). A bullet like this has a mass of around 15g and leaves the gun at 288m/s. Calculate the
kinetic energy in a bullet like this.
2.Aside from shooting bad guys, Bond has a lot off success with, ummm, the ladies. Imagine he is resting in bed one morning
1 m off the ground and that his mass is 63.5 kg. What is his potential energy relative to the ground when he in bed?
3. Do answers from (1) and (2) surprise you? Why is a bullet more damaging than falling out of bed from a height of 1 m?
2. I think i have to use the formula of kinetic energy. Kinetic energy = (mv^2)2 and gravitational potential energy = mgh
sorry i can't use the codes properly so i wrote it this way
3. For number 1 i did
E_k=(mv^2)/2
= (0.015)(288^2)/2
=622.05 J
=6.22 x 10^2 J
so the kinetic energy is 6.22 x 10^2 J
Is this approximation correct since the question has 3 sig figs?
for number 2 i did
Eg=mgh
=63.5 x 9.80 x 1
=622.3 J
=6.22 x 10^2 J
so the gravitational potential enegry is 6.22 x 10^2 J
Is it also appropriate?
for number 3 i wrote
A bullet is more damaging than falling out of bed from height of 1 m because a bullet with its smaller surface area causes more impact on the small area thus creating more damage where is the pressure by falling one meter is spread through the whole body enabling the body to dissipate the damage and get less hurt.
Is it accurate?
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