Why is (B) Incorrect in This Electrostatics Question?

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Homework Help Overview

The discussion revolves around a question regarding the properties of conductors under electrostatic conditions, specifically focusing on the correctness of statement (B) which claims that charge placed on the surface of a conductor always spreads evenly over the surface.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the reasoning behind why statement (B) is considered incorrect, contrasting it with statement (E) which is identified as correct. Some participants discuss the distribution of charge on conductors and its implications for electric potential.

Discussion Status

There is an ongoing examination of the nuances between statements (B) and (E). Some participants provide insights into the behavior of charge distribution on conductors, suggesting that the charge density varies based on the geometry of the surface rather than being uniformly spread.

Contextual Notes

Participants note the ambiguity in the wording of options (B) and (E), indicating that the interpretation of charge distribution may depend on the specific conditions or assumptions made about the conductor's surface.

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Homework Statement




Which of the following statements about conductors under electrostatic conditions is true?
(A) Positive work is required to move a positive charge over the surface of a conductor.
(B) Charge that is placed on the surface of a conductor always spreads evenly over the surface.
(C) The electric potential inside a conductor is always zero.
(D) The electric field at the surface of a conductor is tangent to the surface.
(E) The surface of a conductor is always an equipotential surface.

The Attempt at a Solution



I picked (B), but apparently the answer is (E)

Anyone have a clue... why (B) is incorrect?
 
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option E is correct.
 


JhonMoney said:
option E is correct.

Yeah...because I told you.
 


Check your textbook. It gives some examples. Charge is densest where the radius of curvature is smallest and positive. In places where the surface is concave (radius of curvature is negative) there will be practically no excess charge. The charge is distributed so as to make the surface be an equipotential surface. (I know that's the given answer.) but since the E field everywhere in the conductor is zero, the whole conductor, including the surface, is all at the same potential.
 


The charge gets distributed so as to make the surface be an equipotential surface. In presence of an external non-uniform magnetic field, charge density will vary accordingly, to maintain equipotentiality.
 


the choices B and E are a bit ambiguous but i think this is the distinguishing answer your after.
charge on a surface is not spread evenly over the surface, the surface changes to accept the charge placed upon it.
option B suggest charge is spread evenly over surface
option E says surfaces changes such that charge is spread evenly
 

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