Why is current not considered to be a vector?

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Current is not treated as a vector primarily because it can flow in two directions, which limits its directional representation. While current has both magnitude and direction, it is often considered a scalar quantity in practical applications. The Biot-Savart Law and the definition of current as the integral of current density over an area highlight its scalar nature. The discussion also touches on the relationship between current density and drift velocity, suggesting that while current density can be vectorial, the overall current remains scalar. This distinction is crucial for understanding how current is utilized in electromagnetism.
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Homework Statement



Currently, I am going through the magnetism section of my University Physics II course and I recognized that current has a magnitude and a direction. So, I was wondering why is that we do not treat current as a vector (Since, the direction current moves in can be represented using a unit vector.)?

Homework Equations



Biot-Savart Law

<br /> {d{\vec{B}}} = {{\frac{{\mu}_{0}}{4{\pi}}}{\cdot}{\frac{Id{\vec{s}}{\times}{\vec{r}}}{{r}^{3}}}}<br />

<br /> {J} = {\frac{I}{A}}<br />

<br /> q = n_{e}e, {\textcolor[rgb]{1.00,1.00,1.00}{.}}{\textcolor[rgb]{1.00,1.00,1.00}{.}}{\textcolor[rgb]{1.00,1.00,1.00}{.}}{n_{e}} = \pm1, \pm 2, \pm 3,...,<br />

e \equiv elementary charge

<br /> {n_{e}} = {\pm}N, {\textcolor[rgb]{1.00,1.00,1.00}{.}}{\textcolor[rgb]{1.00,1.00,1.00}{.}}{\textcolor[rgb]{1.00,1.00,1.00}{.}}{N} = 1, 2, 3,...,<br />

<br /> {N_{V}} = \frac{n_{e}}{V}<br />

<br /> {n_{e}} = {N_{V}}{V}<br />

The Attempt at a Solution



I guess, we do not treat current as a vector because we recognize that any given current can go in two possible directions. Either forward or backward. So, because of the limit on the directions current can take we consider it a scalar? Is that right?

Thanks,

-PFStudent
 
Last edited:
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Hey,

dst said:

Thanks for the link dst. I understand now why it is difficult to consider current as a vector. In addition, I remembered now that current can be defined as follows,

<br /> {I} = {\int_{}^{}}{\vec{J}}{\cdot}{d{\vec{A}}}<br />

and

<br /> {I} = {\frac{dq}{dt}}<br />

However, what if you take,

<br /> {\vec{J}} = {{N_{V}}{e}{\vec{v}_{d}}}<br />

and rewrite as,

<br /> {{J}{\hat{u}}} = {{N_{V}}{e}{{v}_{d}}{\hat{u}}}<br />

Where, {\hat{u}} is some unit vector.

And rearranging as,

<br /> {{I}{\hat{u}}} = {{n_{e}}{e}{{v}_{d}}{A}{\hat{u}}}<br />

Why would the above be considered incorrect?

Thanks,

-PFStudent
 
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