Why is gravity taken as positive?

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1. An elevator (mass 4700 kg) is to be designed so that the maximum acceleration is 6.80×10-2. What is the maximum force the motor should exert on the supporting cable?


Force Diagram:

Force Tension
|
elevator
|
mg


3. FT = ma + mg
4700[(0.068(-9.8) - 9.8)]
= -435178.8N
but the answer should be positive. Why isn't gravity negative?
 
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Why is it F = ma + mg? Why not F + ma = mg? Why not F + mg = ma? Why not something else?
 
voko said:
Why is it F = ma + mg? Why not F + ma = mg? Why not F + mg = ma? Why not something else?

Because the ƩF = ma
ƩF = FT - mg
So FT - mg = ma
=> FT = ma + mg
 
whitehorsey said:
Because the ƩF = ma
ƩF = FT - mg
So FT - mg = ma
=> FT = ma + mg

Then in the bolded line, acceleration due to gravity and hence weight is taken as negative whilst tension FT is taken as positive. So the resultant force ma is

ma =FT + (-mg) = FT - mg
 
Applying Newton's Second Law:
m[itex]\ddot{y}[/itex]=FT-mg

g here is just +9.8. The "downward" direction of gravity is already taken care of by the minus sign in :

FT-mg

Rewriting it as
FT=m([itex]\ddot{y}[/itex]+g)
Just plug and chug...

You should get a positive tension force
 
whitehorsey said:
Because the ƩF = ma
ƩF = FT - mg
So FT - mg = ma
=> FT = ma + mg

Since that takes care of the "negative" direction of gravity, you should not further assume that g is negative like you did originally.
 
Thanks everyone!