rbj said:
not from a POV of natural units. the mass of even a proton or neutron is exceedingly small (in terms of the natural unit of mass).
But Planck units change as the number of spacetime dimensions changes.
The gravitational constant in [itex]D[/itex] dimensions is given by
[tex]G^{\left( D \right)} = G \left( l_{C} \right)^{D-4},[/tex]
where [itex]G[/itex] is the usual gravitational constant and [itex]l_C[/itex] is the "cirumference of compactification" of the extra spatial dimensions.
The Planck mass, for example, is the product of appropriate powers of [itex]G^{\left( D \right)}[/itex], [itex]c[/itex], and [itex]\hbar[/itex]. When I work this out for, say, [itex]D = 6[/itex] and an [itex]l_C[/itex] of 10 microns, I get much less discrepancy between the Planck mass and the mass of fundamental particles, and between the Planck mass and the Planck charge (if gravity and not electromagnetism leaks into the extra dimensions).
This why the work at the University of Washington is so important.
Chapter 3 of Zwiebach's book A First Course in String Theory gives a readable presentation of these ideas. Problems 3.9 and 3.10 are quite interesting.
Zwiebach points out that this just trades the mass hierarchy problem for a length hierarchy problem. Why is the Planck length so much smaller than than the compactification scale?