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Why was logx less than or equal to x-1 for all x?
Thanks in advance for your help!
Thanks in advance for your help!
The inequality log(x) ≤ x - 1 holds true for all x in the domain of real numbers. At x = 1, both log(1) and 1 - 1 equal zero, confirming the equality at this point. Analyzing the derivatives of the functions log(x) and x - 1 reveals that the derivative of log(x) is 1/x, which is always less than or equal to 1 for x > 0, while the derivative of x - 1 is constant at 1. This indicates that log(x) grows slower than x - 1 for all x > 0.
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