Why is magnification defined as the ratio of eye and objective lens resolution?

[Marketo]

The telescope magnification is given by the measure of the resolution power of the eye divided by the resolution power of the objetive lens. I just want to know why a magnification can be defined as the ratio of these two kinds of resolution, I need a justification of this statement.

 

[xts]

Where have you found such definition of magnification?
I would also like to see its justification

See: http://en.wikipedia.org/wiki/Magnification

 

[Marketo]

Where have you found such definition of magnification?
I would also like to see its justification

See: http://en.wikipedia.org/wiki/Magnification

Please check The physics book of Marcelo Alonso and Edward J. Finn in the chapter of geometry of waves when talking about telescope

 

[xts]

Please check The physics book of Marcelo Alonso and Edward J. Finn in the chapter of geometry of waves when talking about telescope

Ouch - you are sending me to a library having English science textbooks (it had not been translated to my language, so I won't get it in my local library)... Not this week...

 

[JeffKoch]

The telescope magnification is given by the measure of the resolution power of the eye divided by the resolution power of the objetive lens. I just want to know why a magnification can be defined as the ratio of these two kinds of resolution, I need a justification of this statement.

It is not defined this way, it is defined as the ratio of focal lengths of the telescope and the eyepiece. Resolving power is not a clearly defined concept unless you also state how you define resolving power, and in any case it makes no sense in this context. Either you misunderstood the text and did not look into it any farther, or the text is making some kind of analogy or stating how (I don't know how) the precisely defined number "magnification" can be stood in terms of resolving power of the two components. I also presume you meant "eyepiece" when your wrote "eye".