Why Is My Calculation of the Wheel's Moment of Inertia Incorrect?

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SUMMARY

The calculation of the wheel's moment of inertia with respect to eight rods is incorrectly derived in the discussion. The correct formula for the total moment of inertia is (3m2/8 + m1) * r^2, where m1 is the mass of the wheel and m2 is the mass of one rod. The user mistakenly multiplied the moment of inertia of the wheel by eight, leading to an incorrect total. The application of Steiner's theorem was misapplied, resulting in confusion regarding the contributions of the wheel and rods.

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dannee
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Homework Statement




i've attched a picture of the wheel, which need to calculate moment of intertia with respect to 8 rods.

i've tried to use stiener rule but it's not getting the answer,

moment of wheel is (m1*r^2)/2
moment of rod is (m2*r^2/3)

i use the rule i total = icm + mr^2

so it's 8*( (m1*r^2)/2 + (m2*r^2)/3 )

what am i missing?



Homework Equations



m1 = mass of wheel
m2 = mass of rod
r = length of rod

The Attempt at a Solution

 

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dannee said:
moment of wheel is (m1*r^2)/2
Revisit this formula.

so it's 8*( (m1*r^2)/2 + (m2*r^2)/3 )
There are 8 spokes but only 1 wheel.
 
that's right, 8 * 3(m2*r^2), i refer the moment of wheel is (m1*r^2)/2 and sum them,

but the correct answer is (3m2/8 + m1) * r^2
 
dannee said:
that's right, 8 * 3(m2*r^2), i refer the moment of wheel is (m1*r^2)/2 and sum them,
(1) Your formula for the moment of inertia of the wheel portion is incorrect.
(2) In your final result in post #1 you multiplied all terms by 8, thus counting the wheel 8 times.

but the correct answer is (3m2/8 + m1) * r^2
Double check that answer; looks like a typo.
 

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