Why Is My Rigid Body Equilibrium Equation Incorrect?

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Homework Help Overview

The discussion revolves around the equilibrium equations for a rigid body, specifically focusing on the moments acting on a vertical wall subjected to water pressure. The original poster attempts to derive an equation for the sum of moments but expresses uncertainty about the correctness of their approach and the resulting value for height (h).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formulation of torque equations, questioning the inclusion of certain variables such as 'b' in the torque expression. There are attempts to clarify the relationship between the height of the wall and the forces acting on it, as well as the moment arms used in the calculations.

Discussion Status

The conversation is ongoing, with participants providing insights into the relationships between pressure, force, and torque. Some guidance has been offered regarding the correct interpretation of the height of the wall and its impact on the calculations, but no consensus has been reached on the original poster's approach.

Contextual Notes

There is a mention of the original poster's confusion regarding the dimensions involved in the problem, particularly the height of the wall versus other variables. The discussion reflects a need for clarity on how to properly apply the principles of fluid mechanics to the scenario presented.

dbag123
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Homework Statement
Determine the lenght of h with respect to b so that the water flows.
Relevant Equations
sum of moments at the hinge
Hello
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Ihave gotten as far as coming up with an equation for the sum of moments and it goes as follows: bh*1/2b-1/2hb*1/3b=0 the answer for h i get is wrong and i don't know if i am missing something. moment arm on the b is 1/2b and the moment arm on h is 1/3h because of the way water pressure works , meaning its a uniform load in the shape of triangle. bh is my way of writing the force as a point load acting on the levers. The answer to this problem is supposed to be h= √3 *b. Any help is appreciated.
 
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dbag123 said:
sum of moments and it goes as follows: bh*1/2b-1/2hb*1/3b=0
In your expression for the torque on the vertical wall, why does b enter in?
 
jbriggs444 said:
In your expression for the torque on the vertical wall, why does b enter in?
my thinking was that replacing the acting force with the area of water would be of help, but yeah its not helping
 
dbag123 said:
my thinking was that replacing the acting force with the area of water would be of help, but yeah its not helping
I do not think that you are catching on. The wall is h meters high, not b meters high.
 
jbriggs444 said:
I do not think that you are catching on. The wall is h meters high, not b meters high.
My thinking was that the resultant force acting on the vertical Wall would be 1/2hb(area of triangle) and the moment arm 1/3h from the hinge and the product of these 2 then the moment
 
dbag123 said:
My thinking was that the resultant force acting on the vertical Wall would be 1/2hb(area of triangle) and the moment arm 1/3h from the hinge and the product of these 2 then the moment

The average pressure on the wall is proportional to the height of the wall. The higher the wall, the higher the average pressure.

The total force on the wall is proportional to the height of the wall [times the average pressure]. The higher the wall, the higher the total force.

The total torque on the wall is proportional to the height of the wall [times the total force]. The higher the wall, the higher the total torque.

The length of the floor segment does not enter into the calculation of torque on the vertical wall. You can use a triangle to calculate the force on the vertical wall. Just not the particular triangle you have in mind.
 
jbriggs444 said:
The average pressure on the wall is proportional to the height of the wall. The higher the wall, the higher the average pressure.

The total force on the wall is proportional to the height of the wall [times the average pressure]. The higher the wall, the higher the total force.

The total torque on the wall is proportional to the height of the wall [times the total force]. The higher the wall, the higher the total torque.

The length of the floor segment does not enter into the calculation of torque on the vertical wall. You can use a triangle to calculate the force on the vertical wall. Just not the particular triangle you have in mind.

And that's why my moment equation does not work. Thank you.
 

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