Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Why is p=fv different than calculatingit manually

  1. Oct 4, 2012 #1
    A 49.0 sprinter, starting from rest, runs 45.0in 7.10 at constant acceleration.
    What is the magnitude of the horizontal force acting on the sprinter?


    okay so I got 87.5N which is correct

    Then it asks:
    What is the sprinter's power output at 1.70 , 3.60 , and 5.50 ?


    why is it when you use d=1/2*a*t^2
    it is wrong

    see:
    (1/2)*(1.78)(1.7)^2 = 2.57 for distance

    then 2.57*87.5= 224 joules

    then for power it is 224/1.7 = 131

    but the answer is exactly twice that

    if you use p=f*v you get the correct answer straight away

    shouldn't these be the same?
     
  2. jcsd
  3. Oct 4, 2012 #2

    cjl

    User Avatar

    Because the power output isn't constant, and when you're calculating the power using the distance traveled and the time elapsed, you're finding the average power up to that point, not the instantaneous power.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Why is p=fv different than calculatingit manually
  1. Why more than 3? (Replies: 8)

Loading...