Why is Sequence 1, 4, 7, 10 Written as 3n-2 or 3n+2?

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Homework Help Overview

The discussion revolves around the representation of a numerical sequence, specifically the sequence 1, 4, 7, 10, and its general term forms, a_n = 3n-2 and a_n = 3n+2. Participants are exploring the reasoning behind using different forms for the same sequence and the implications of starting the count from different integers.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question why the sequence can be represented in two different ways and whether one form is more advantageous or mathematically correct than the other. There is also a discussion about the implications of starting the sequence count from 0 versus 1.

Discussion Status

Some participants have provided insights into the differences in counting methods and clarified that the choice of representation does not significantly impact the mathematical correctness. However, there is no explicit consensus on a preferred method, and various interpretations of the sequence representations are being explored.

Contextual Notes

Participants note that different textbooks may adopt different conventions regarding the starting point of sequences, which may influence the choice of general term representation.

Natasha1
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Hi,

Could anyone please explain to me very simply why in a sequence say 1, 4, 7, 10,... which has the general term form: a_n = 3n-2 can also be written as 3n+2?

Why do some people use 3n+2 rather than 3n-2, what advantage has that got? Is it actually more mathematically correct to write 3n+2?

So 2n-2 or 2n+2 would be for a sequence 1, 2, 3, 4, 5,...
4n-1 or 4n+3 would be for 3, 7, 11, ...

Thanks

Nat
 
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Surely you mean 3n+1 with n starting from 0??
 
If an= 3n-2 then 3(n+1)- 2= 3n+3-2= 3n+1. The only difference is that with an= 3n-2 you have a1= 1, a2= 4, etc. while with an= 3n+1 it is a0= 1, a1= 4, etc. Just a difference in where you start counting.
There is no real advantage- just that some people don't like to start counting with 0!


"So 2n-2 or 2n+2 would be for a sequence 1, 2, 3, 4, 5,... "

No- 2(1)-2= 0, 2(2)-2= 2, but 2(3)- 2= 4 not 3. It should be obvious that 2n- 2 and 2n+ 2 are always even numbers. Did you mean 2, 4, 6, ...?


"4n-1 or 4n+3 would be for 3, 7, 11, ..."
Yes, one starts with n= 1, the other with n= 0.
 
HallsofIvy said:
If an= 3n-2 then 3(n+1)- 2= 3n+3-2= 3n+1. The only difference is that with an= 3n-2 you have a1= 1, a2= 4, etc. while with an= 3n+1 it is a0= 1, a1= 4, etc. Just a difference in where you start counting.
There is no real advantage- just that some people don't like to start counting with 0!


"So 2n-2 or 2n+2 would be for a sequence 1, 2, 3, 4, 5,... "

No- 2(1)-2= 0, 2(2)-2= 2, but 2(3)- 2= 4 not 3. It should be obvious that 2n- 2 and 2n+ 2 are always even numbers. Did you mean 2, 4, 6, ...?


"4n-1 or 4n+3 would be for 3, 7, 11, ..."
Yes, one starts with n= 1, the other with n= 0.

Yes sorry I did mean 2, 4, 6, 8, ...
 
I don't know about HallsofIvy, but I'm an inveterate "from zero"-counter..
 
Last edited:
arildno said:
I don't know about HallsofIvy, but I'm an inveterate "from zero"-counter..

Unfortunately (or fortunately depending on your preference), many textbooks count from 1.
 

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