Why is specific mechanical energy in fluid mechanics divided by mass?

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custer
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Why does [tex]Emec= P/\rho + v^2/2 + gz[/tex] ?
The units resulting from the three expressions are [tex]m^2/s^2[/tex]
but unit for energy is supposed to be Joules? where does the mass go? If the three expressions were already divided by the mass then why Emec still remains as Emec?
 
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Hi custer! :smile:

(have a rho: ρ :wink:)
custer said:
Why does [tex]Emec= P/\rho + v^2/2 + gz[/tex] ?

Which book did you get that equation from? :confused:

The LHS should be the mechanical energy per unit mass.

(Compare it with ε, the internal energy per unit mass, or "specific internal energy").

See the PF Library on pressure and Bernoulli's equation :wink:
 
got it from a slide in my lecture note.. no wonder ;P
thank you :)