Why is the area of a cross section not pi * r^2 for a rod?

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The area of a cross section for a rod is calculated using the formula πD²/4 instead of πr² because D represents the diameter, which is the measurement commonly used in practice. While the radius (r) is half the diameter, using diameter simplifies calculations in engineering contexts where diameter is often the given measurement. This distinction is important for accurate engineering calculations and design. Understanding this formula helps clarify the relationship between diameter and radius in cross-sectional area calculations. Accurate area calculations are crucial in mechanical engineering applications.
ktpr2
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I'm going through my intro to mechanical engineering material and there was one thing I was never clear on:

If you have a cross section of a rod, why isn't its' area at a cross section pi * r^2 as a opposed to piD^2/4, where D is the diameter?
 
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Becasue people are actually measuring the diameter...?

Daniel.
 
whoops. That makes sense :D
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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