What does cross section area mean when dealing with stress/strain?

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Jay520
What does "cross section area" mean when dealing with stress/strain?

Homework Statement



For clarification, here is an example problem:

A circular steel wire 2 m long must stretch no more than 0.25 cm when a tensile force of 400 N is applied to each end of the wire. What minimum diameter is required for the wire?

Relevant equations

FL = YA(ΔL)Apparently, the cross section area for this object is simply pi*r^2 (as for any circle). Can someone tell me exactly what the cross section area is supposed to refer to? I thought it was the area of the plane of the object perpendicular to the applied force, but apparently I'm wrong or not understanding something properly.
 
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I don't know what the definition of "cross section area" is. At least not well enough to apply it to the context of elasticity physics problems.
 
When you put the wire in tension, the tensile stress is calculated using the circular cross-section of the wire.
The tensile stress σ = F/A, where F is the tensile load (Newtons) and A is the cross section area (m^2), and the stress σ has units of pascals (N/m^2)

For a circular wire, A = πR[itex]^{2}[/itex] or πD[itex]^{2}[/itex]/4, where R (radius) or D (diameter) of the wire are measured in meters.

The elongation of an object undergoing a tensile load is

δ = FL/AE

where

F = tensile load (Newtons)
L = unloaded length of the object (meters)
A = cross sectional area of the object (m^2)
E = modulus of elasticity of the material (Pa)

The cross section just refers to the shape of the loaded object which results from its intersection with a plane oriented normal to the applied load.