Why Is the Average Speed Not Simply the Arithmetic Mean of Two Speeds?

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Average speed cannot be calculated simply as the arithmetic mean of two speeds due to the differing distances traveled at each speed. In the example, a person travels half the distance at 30 mph and the other half at 60 mph, leading to a non-linear average speed calculation. To find the overall average speed, one must consider the total distance and total time taken for the journey. By using dimensional analysis, the relationship between speed, distance, and time can be established to derive the correct average speed. The final average speed for the entire journey is not merely 45 mph, but requires a more detailed calculation.
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I just wanted to know how to find average speed without knowing the distance. I know average speed is defined as total distance / change in time but what would you do
a person travels to a friend's house and when he is halfway there, he figures out that he has been averaging 30 mph. He drives the last half of the trip at 60 mph.
What is Joe’s average speed for the entire journey?

I figured it was just 30 + 60 divided by 2 but apparently i am wrong. anyone can help?
 
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It is not quite that linear because you cover more per time going 60 miles per hour than 30 miles per hour.

We will use dimensional analysis just to make sure our operations are making sense.

60 (m/h) * x (h) + y (m/h) * x (h) = c miles

we also know that 30 (m/h) = c (m) / 2x (h)

so 2x (h) = c (m) / 30 (m/h)

So now you can solve for x, the c's will cancel out (cause it doesn't depend on the distance traveled), solve then for y, and you'll get the answer.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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