Why total time taken s₁/v₁ + s₂/v₂ + s₃/v₃ in average speed?

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The discussion centers on understanding the formula for average speed, specifically how total time is calculated as the sum of distances divided by their respective speeds (s₁/v₁ + s₂/v₂ + s₃/v₃). Participants clarify that average speed is derived from total distance divided by total time, emphasizing the need to define variables clearly. The conversation also touches on the average speed formula for round trips, highlighting the importance of correctly applying distance and time calculations. Misunderstandings about notation and the need for clear problem statements are addressed. Overall, the thread emphasizes the foundational concept of average speed as distance over time.
  • #31
Indranil said:
Vavg = d1 + d2 / t1 + t2?
What are d1 and d2? We have two points, A and B with distance d between them.

[Note that parentheses matter]
 
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  • #32
jbriggs444 said:
What are d1 and d2? We have two points, A and B with distance d between them.

[Note that parentheses matter]
Vavg = s / t ?
 
  • #33
Indranil said:
Vavg = s / t ?
What's s? We have two points A and B with distance d between them.
 
  • #34
jbriggs444 said:
What's s? We have two points A and B with distance d between them.
could you mention the equation, please?
 
  • #35
Indranil said:
could you mention the equation, please?
No. That's your job.
 
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  • #36
jbriggs444 said:
No. That's your job.
Vavg = 2d / t?
 
  • #37
Indranil said:
Vavg = 2d / t?
Could anyone clarify me please Vavg = 2d / t? I am waiting for the replies.
 
  • #38
Indranil said:
t1 + t2 = d / v1 + d / v2, t = d (v1 + v2) / v1v2,
Yes

Vavg = d / t
No, in the problem you are considering the total distance is d + d = 2d because you travel distance d from point A to point B and then travel distance d again when you go from point B back to point A.

but the equeation is 2v1v2 / v1 + v2
You are complicating the discussion by writing fractions incorrectly. You omit paretheses that are needed.
You write "2v1v2/ v1 + v2" when you actually mean "2v1v2/ (v1 + v2)"
 
  • #39
Stephen Tashi said:
YesNo, in the problem you are considering the total distance is d + d = 2d because you travel distance d from point A to point B and then travel distance d again when you go from point B back to point A.You are complicating the discussion by writing fractions incorrectly. You omit paretheses that are needed.
You write "2v1v2/ v1 + v2" when you actually mean "2v1v2/ (v1 + v2)"
I got it now. I will check myself. please find my faults so that I can improve myself in Physics. I am learning a lot from this site. one more equation
If t₁ = t₂ = t₃ =...tn, Vav = (v₁ + v₂ +...+ vn)t / nt
What's the concept behind the equation above? Could you clarify it, please?
 
  • #40
Indranil said:
one more equation
If t₁ = t₂ = t₃ =...tn, Vav = (v₁ + v₂ +...+ vn)t / nt
What's the concept behind the equation above?

The proper format of a physics problem is to have a statement of the problem in words. In that statement, the variables are defined. After the variables are defined in words, equations are written.

You give an equation, but you omit the description of the problem in words and you omit defining the variables.

Many of the homework advisors are capable of seeing an equation and guessing what words describe the problem. However, if you rely on other people to "read your mind", you won't learn to write clearly.

Explain the situation and define the variables that are used.
 
  • #41
Stephen Tashi said:
The proper format of a physics problem is to have a statement of the problem in words. In that statement, the variables are defined. After the variables are defined in words, equations are written.

You give an equation, but you omit the description of the problem in words and you omit defining the variables.

Many of the homework advisors are capable of seeing an equation and guessing what words describe the problem. However, if you rely on other people to "read your mind", you won't learn to write clearly.

Explain the situation and define the variables that are used.
Thank you for your kind advice. I'll try to follow.
If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / nt
What is the concept behind this formula?
 
  • #42
What does 'tn' and 'Vn' mean in the equation below?
'If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / nt' Could you explain please?
 
  • #43
You have ##n## time intervals, all equally long. ##t_1## is the length of the first interval, ##t_2## is the length of the second one, and so forth.
 
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  • #44
Nugatory said:
You have ##n## time intervals, all equally long. ##t_1## is the length of the first interval, ##t_2## is the length of the second one, and so forth.
I don't understand clearly. Could you explain it in detail, please?
 
  • #45
Indranil said:
Thank you for your kind advice. I'll try to follow.
If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / nt
What is the concept behind this formula?
If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / nt
What is the concept behind this formula?
I am waiting for the replies
 
  • #46
Indranil said:
If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / nt
What is the concept behind this formula?
I am waiting for the replies

You have not yet made a complete description of the problem in words. If the problem is written in English, please quote the entire problem. Don't merely quote fragments from it.

If you are translating the problem from another language into English, try to translate each sentence.
 
  • #47
Indranil said:
If t₁ = t₂ = t₃ =...= tn, Then we have Vavg = (v₁ + v₂ +...+Vn)t / nt
What is the concept behind this formula?
The concept behind this formula is the same as all the others: Vave = Distance/Time. Of all the formulas you've been asking about, this basic definition of average speed is the one you need to have down cold. All the rest can be derived from this with a little algebra.

You seem to be obsessing over several formulas that are only useful in very specific situations. (The formula quoted in this post is an example of that -- it's only true under very specific assumptions.) Unless you specify the problem you are trying to solve -- and thus define what the variables mean in your equations -- we can only guess at what you're trying to do. (Admittedly, we are pretty good guessers. But we shouldn't have to guess.)
 
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