Why Is the Average Speed Not Simply the Arithmetic Mean of Two Speeds?

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SUMMARY

The average speed for a journey where a person travels half the distance at 30 mph and the other half at 60 mph is not simply the arithmetic mean of the two speeds. Instead, the correct approach involves dimensional analysis to account for the varying speeds over equal distances. By setting up the equation 60 (m/h) * x (h) + 30 (m/h) * x (h) = c miles, and knowing that 30 (m/h) = c (m) / 2x (h), one can solve for the total average speed. The final average speed for the entire journey is 40 mph.

PREREQUISITES
  • Understanding of average speed calculations
  • Familiarity with dimensional analysis
  • Basic algebra skills
  • Knowledge of speed units (miles per hour)
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  • Study the concept of harmonic mean and its application in average speed calculations
  • Learn about dimensional analysis techniques in physics
  • Explore real-world examples of average speed in varying conditions
  • Investigate the implications of speed variations on travel time
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Students, educators, and anyone interested in physics or mathematics, particularly those looking to deepen their understanding of average speed calculations and dimensional analysis.

marco101
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I just wanted to know how to find average speed without knowing the distance. I know average speed is defined as total distance / change in time but what would you do
a person travels to a friend's house and when he is halfway there, he figures out that he has been averaging 30 mph. He drives the last half of the trip at 60 mph.
What is Joe’s average speed for the entire journey?

I figured it was just 30 + 60 divided by 2 but apparently i am wrong. anyone can help?
 
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It is not quite that linear because you cover more per time going 60 miles per hour than 30 miles per hour.

We will use dimensional analysis just to make sure our operations are making sense.

60 (m/h) * x (h) + y (m/h) * x (h) = c miles

we also know that 30 (m/h) = c (m) / 2x (h)

so 2x (h) = c (m) / 30 (m/h)

So now you can solve for x, the c's will cancel out (cause it doesn't depend on the distance traveled), solve then for y, and you'll get the answer.
 
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