The bond order of B22- is calculated as 1.5 using the formula (Number of bonding electrons - Number of antibonding electrons)/2. In this case, B22- has 3 bonding electrons and 0 antibonding electrons, leading to the calculation (3-0)/2 = 1.5. This calculation is confirmed as correct, despite initial confusion regarding its accuracy. The bond order indicates a stable molecular structure for the B22- ion.
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stacker said:Homework Statement
What is the bond order of B22-
Homework Equations
(Number of bonding electrons - number of antibonding electron)/2
The Attempt at a Solution
(3-0)/2 = 1.5, which is wrong. What's going on?