# Is my solution correct? (Electromagnetism problem)

## Homework Statement H1=10
H2=-10
B1=1.5
B2=-1.5

## Homework Equations

(change)Uloop = (change)H2*B2 + (change)H1*B1

## The Attempt at a Solution

=(H1-H2)(B2-B1)
=(10-(-10))(-1.5-1.5)
=-60 j/m^3

## Answers and Replies

rude man
Homework Helper
Gold Member
You're on the right track but you have computed the energy dissipated in 1 cycle (but with the wrong units). Now convert the energy per cycle to the time rate of energy dissipation.

You're on the right track but you have computed the energy dissipated in 1 cycle (but with the wrong units). Now convert the energy per cycle to the time rate of energy dissipation.

So, it sould be someting like ((H1-H2)(B2-B1))*f ?

Where did I go wrong with units?
Is it j/m^2 due to area (not volume)?

rude man
Homework Helper
Gold Member
You're on the right track but you have computed the energy dissipated in 1 cycle (but with the wrong units). Now convert the energy per cycle to the time rate of energy dissipation.

So, it should be someting like ((H1-H2)(B2-B1))*f ?
Yes. A lot like! :-)
Where did I go wrong with units?
Is it j/m^2 due to area (not volume)?
You didn't go wrong. I did. The per-cycle energy dissipation units are J m-3 just as you said. Except the final answer is of course in J sec-1m-3.

Yes. A lot like! :-)

You didn't go wrong. I did. The per-cycle energy dissipation units are J m-3 just as you said. Except the final answer is of course in J sec-1m-3.
So, final answer sould be:
=((H1-H2)(B2-B1))*f
=-60 * 50
=-3000 j sec^-1 m^-3
Makes sense. Thanx for help :)

rude man
Homework Helper
Gold Member
So, final answer sould be:
=((H1-H2)(B2-B1))*f
=-60 * 50
=-3000 j sec^-1 m^-3
Makes sense. Thanx for help :)
OK, except no minus sign. Energy is dissipated in heat.