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Is my solution correct? (Electromagnetism problem)

  • Thread starter loki4000
  • Start date
  • #1
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Homework Statement


29lcoyq.jpg

H1=10
H2=-10
B1=1.5
B2=-1.5

Homework Equations


(change)Uloop = (change)H2*B2 + (change)H1*B1

The Attempt at a Solution


=(H1-H2)(B2-B1)
=(10-(-10))(-1.5-1.5)
=-60 j/m^3
 

Answers and Replies

  • #2
rude man
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You're on the right track but you have computed the energy dissipated in 1 cycle (but with the wrong units). Now convert the energy per cycle to the time rate of energy dissipation.
 
  • #3
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You're on the right track but you have computed the energy dissipated in 1 cycle (but with the wrong units). Now convert the energy per cycle to the time rate of energy dissipation.
So, it sould be someting like ((H1-H2)(B2-B1))*f ?

Where did I go wrong with units?
Is it j/m^2 due to area (not volume)?
 
  • #4
rude man
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You're on the right track but you have computed the energy dissipated in 1 cycle (but with the wrong units). Now convert the energy per cycle to the time rate of energy dissipation.
So, it should be someting like ((H1-H2)(B2-B1))*f ?
Yes. A lot like! :-)
Where did I go wrong with units?
Is it j/m^2 due to area (not volume)?
You didn't go wrong. I did. The per-cycle energy dissipation units are J m-3 just as you said. Except the final answer is of course in J sec-1m-3.
 
  • #5
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Yes. A lot like! :-)

You didn't go wrong. I did. The per-cycle energy dissipation units are J m-3 just as you said. Except the final answer is of course in J sec-1m-3.
So, final answer sould be:
=((H1-H2)(B2-B1))*f
=-60 * 50
=-3000 j sec^-1 m^-3
Makes sense. Thanx for help :)
 
  • #6
rude man
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So, final answer sould be:
=((H1-H2)(B2-B1))*f
=-60 * 50
=-3000 j sec^-1 m^-3
Makes sense. Thanx for help :)
OK, except no minus sign. Energy is dissipated in heat.
 

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