- #1

- 15

- 0

## Homework Statement

H1=10

H2=-10

B1=1.5

B2=-1.5

## Homework Equations

(change)Uloop = (change)H2*B2 + (change)H1*B1

## The Attempt at a Solution

=(H1-H2)(B2-B1)

=(10-(-10))(-1.5-1.5)

=-60 j/m^3

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter loki4000
- Start date

- #1

- 15

- 0

H1=10

H2=-10

B1=1.5

B2=-1.5

(change)Uloop = (change)H2*B2 + (change)H1*B1

=(H1-H2)(B2-B1)

=(10-(-10))(-1.5-1.5)

=-60 j/m^3

- #2

- 7,882

- 798

- #3

- 15

- 0

So, it sould be someting like ((H1-H2)(B2-B1))*f ?

Where did I go wrong with units?

Is it j/m^2 due to area (not volume)?

- #4

- 7,882

- 798

Yes. ASo, it should be someting like ((H1-H2)(B2-B1))*f ?

You didn't go wrong. I did. The per-cycle energy dissipation units are J mWhere did I go wrong with units?

Is it j/m^2 due to area (not volume)?

- #5

- 15

- 0

So, final answer sould be:Yes. Alike! :-)lot

You didn't go wrong. I did. The per-cycle energy dissipation units are J m^{-3}just as you said. Except the final answer is of course in J sec^{-1}m^{-3}.

=((H1-H2)(B2-B1))*f

=-60 * 50

=-3000 j sec^-1 m^-3

Makes sense. Thanx for help :)

- #6

- 7,882

- 798

OK, except no minus sign. Energy is dissipated in heat.So, final answer sould be:

=((H1-H2)(B2-B1))*f

=-60 * 50

=-3000 j sec^-1 m^-3

Makes sense. Thanx for help :)

Share:

- Replies
- 38

- Views
- 4K