Why Is the Calculated Force Excessive for Lifting the Barbell?

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The forum discussion centers on an athlete lifting a 470 N barbell with a mass of 86.5 kg, accelerating it over a distance of 0.50 m in 2.0 seconds. The initial calculations provided by the user incorrectly determined the acceleration as 25 m/s², which is inconsistent with the distance covered in the given time. The correct approach involves using kinematic equations to find the actual acceleration and subsequently the total force exerted, which should account for both the weight of the athlete and the barbell.

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An athlete whose mass is 86.5 kg is performing weight-lifting exercises. Starting from the rest position, he lifts, with constant acceleration, a barbell that weighs 470 N. He lifts the barbell a distance of 0.50 m in a time of 2.0 s.


I cannot seem to find the answer to this. This is what i did:

- I found the total force exerted on the feet by doing: 86.5*9.8 + 470N = 1317.7N
- Then I used d = a*t^2 and got that the acceleration is 25m/s^2
- Then i found the mass of the barbell by doing 470N/9.8 and got 47.96kg.
- After using F=ma i added the two forces and got the answer 2516.7N.

This isn't the right answer. What did i do wrong? Any help is appreciated.

Thanks.
 
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hi treyh! :smile:
treyh said:
An athlete whose mass is 86.5 kg is performing weight-lifting exercises. Starting from the rest position, he lifts, with constant acceleration, a barbell that weighs 470 N. He lifts the barbell a distance of 0.50 m in a time of 2.0 s.

i don't understand the question :redface:

is his body remaining stationary (apart from his arms)?

or is his centre of mass also moving up 0.50 m ? :confused:
 
treyh said:
An athlete whose mass is 86.5 kg is performing weight-lifting exercises. Starting from the rest position, he lifts, with constant acceleration, a barbell that weighs 470 N. He lifts the barbell a distance of 0.50 m in a time of 2.0 s.


I cannot seem to find the answer to this. This is what i did:

- I found the total force exerted on the feet by doing: 86.5*9.8 + 470N = 1317.7N
- Then I used d = a*t^2 and got that the acceleration is 25m/s^2
- Then i found the mass of the barbell by doing 470N/9.8 and got 47.96kg.
- After using F=ma i added the two forces and got the answer 2516.7N.

This isn't the right answer. What did i do wrong? Any help is appreciated.

Thanks.

I just read the original post very carefully, but the only question mark I found was at the end of " What did I do wrong?"

I am tempted to reply: " You didn't ask a question?"

The line I highlighted red above is interesting. If an object falls under the influence of gravity - with an acceleration a little under 10 m/s^2 - it covers just under 20m in 2 seconds. This barbell covered only 0.5 m in 2 seconds yet you said the acceleration was 25 m/s^2 - more than double the acceleration due to gravity ??
 

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