Why is the Cartesian Product S×T Empty When T is Empty?

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Homework Help Overview

The discussion revolves around the Cartesian product of sets, specifically examining the case where one of the sets, T, is empty. Participants are exploring why the product S×T results in an empty set when T is empty.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants attempt to understand the definition of the Cartesian product and question how the absence of elements in T affects the formation of ordered pairs. Others suggest examining the definition of the product to identify the implications of an empty set.

Discussion Status

The discussion is active, with participants raising questions about the nature of the Cartesian product and exploring logical reasoning. Some guidance has been offered regarding the definition of the product, and there is an ongoing examination of potential contradictions that arise from assuming S×T is non-empty.

Contextual Notes

Participants are working under the assumption that S is any set while T is specifically defined as the empty set. There is a focus on the implications of this setup for the Cartesian product.

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Homework Statement


Let S be any set and T = ∅. What can you say about the set S×T?

Homework Equations

The Attempt at a Solution


The solution is that S×T=∅. I'm not quite sure why this is though. Is it because there isn't anything in T to give an ordered pair so S×T is empty?
 
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Can you find anything in ##S \times T##?
 
rmiller70015 said:

Homework Statement


Let S be any set and T = ∅. What can you say about the set S×T?

Homework Equations

The Attempt at a Solution


The solution is that S×T=∅. I'm not quite sure why this is though. Is it because there isn't anything in T to give an ordered pair so S×T is empty?

Well, when we write out the definition of AxB, we have:

AxB = {(a,b) | a ∈ A and b ∈ B}

Now, apply this to your set, what do you notice?
 
Math_QED said:
Well, when we write out the definition of AxB, we have:

AxB = {(a,b) | a ∈ A and b ∈ B}

Now, apply this to your set, what do you notice?
There is no element t for the set T. And the set theoretical product does not make sense. Except for (∅,∅).
 
rmiller70015 said:
There is no element t for the set T. And the set theoretical product does not make sense. Except for (∅,∅).

##\emptyset \notin \emptyset##
 
rmiller70015 said:
There is no element t for the set T. And the set theoretical product does not make sense. Except for (∅,∅).

Let SxT = {(s,t)|s ∈ S and t ∈ T}
Suppose that SxT ≠ ∅...

Try to find a contradiction, then follows that S x T = ∅
 
Math_QED said:
Let SxT = {(s,t)|s ∈ S and t ∈ T}
Suppose that SxT ≠ ∅...

Try to find a contradiction, then follows that S x T = ∅
Ok thank you, that makes sense.
 

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