Why is the correction important?

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SUMMARY

The discussion focuses on finding the Taylor series of the function f(x) = x²ln(1+2x²) centered at c = 0. The initial attempt yielded the expression (-1)ⁿ4ⁿx²ⁿ/n, which was incorrect. The correct approach involves recognizing that (2x²)ⁿ equals 2ⁿx²ⁿ, and after making this correction, the final Taylor series can be derived by multiplying by x².

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Soccerdude
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Homework Statement



Find the Taylor series of f(x) = x2ln(1+2x2) centered at c = 0.


Homework Equations



Taylor Series of f(x) = ln(1+x) is Ʃ from n=1 to ∞ of (-1)n-1xn/n

The Attempt at a Solution



I have worked the problem to

(-1)n4nx2n/n

I am not sure where to go from here

Thank You!
 
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Soccerdude said:

Homework Statement



Find the Taylor series of f(x) = x2ln(1+2x2) centered at c = 0.


Homework Equations



Taylor Series of f(x) = ln(1+x) is Ʃ from n=1 to ∞ of (-1)n-1xn/n

The Attempt at a Solution



I have worked the problem to

(-1)n4nx2n/n

I am not sure where to go from here

Thank You!
Well, you seem to have the right idea for the Taylor series of ln(1+2x2). It's not quite right.

[itex]\displaystyle \left(2x^2\right)^n=2^nx^{2n}\ .[/itex]

When you make the correction for that, then just multiply by x2 , to get the Taylor series for x2ln(1+2x2).
 

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