Why Is the d-Orbital Considered in Sc Term Symbols?

[physicisttobe]

Homework Statement

electron configuration of SC

Relevant Equations

...

I've solved further Term Symbol problems. The task is: derive the term symbols of the ground states of the following atoms: a) H, b) F, c) Cu, d) F- , e) P, f) Na, g) Sc

Why is the d-orbital considered here in g)? Why isn't the s orbital taken into account here? The 4s orbital is energetically higher than the 3d orbital, so why don't you look at the 4s orbital. I also post the solution and my approach to this problem. I can't explain why my approach is incorrect. Can someone help me?

my approach:

solution:

 

[mjc123]

The s orbital is full. The net contribution of all filled subshells to L and S is zero, so you only need to consider partially filled subshells. (And I assume 3d¹⁴ is a typo for 3d¹.)

Oh, and if you meant Sc you should have said so. SC is something very different!

 

[physicisttobe]

The s orbital is full. The net contribution of all filled subshells to L and S is zero, so you only need to consider partially filled subshells.

All right, but what about F-? We have the configuration [He]2s^2 2p^6, both orbitals are full.
I thought it would be 1P0 but it's wrong. The solution is 1S0, but I can't explain why 1S0.
I solved this problem like this:

(And I assume 3d¹⁴ is a typo for 3d¹.)

Yes, it's a typo, sorry for that.

Oh, and if you meant Sc you should have said so. SC is something very different!

Oh, sorry, I mean Sc, of course.

The s orbital is full. The net contribution of all filled subshells to L and S is zero, so you only need to consider partially filled subshells. (And I assume 3d¹⁴ is a typo for 3d¹.)

Oh, and if you meant Sc you should have said so. SC is something very different!

 

[TSny]

All right, but what about F-? We have the configuration [He]2s^2 2p^6, both orbitals are full.
I thought it would be 1P0 but it's wrong. The solution is 1S0, but I can't explain why 1S0.

What is your reasoning for selecting $P$ in your solution $^1P_0$?
A full orbital subshell has zero net orbital angular momentum.

 

[berkeman]

Oh, sorry, I mean Sc, of course.

{Fixed in thread title now)

 

[physicisttobe]

What is your reasoning for selecting $P$ in your solution $^1P_0$?
A full orbital subshell has zero net orbital angular momentum.

All right, I get it. Thank you so much for your help!
If any questions arise, I'll get in touch here