Why Is the Derivative Uniqueness Proof Important?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
7 replies · 4K views
NanoMath
Messages
11
Reaction score
0
Proof.png
Hello.
In the proof of uniqueness of ( multi-variable ) derivative from Rudin, I am a little stuck on why the inequality holds. Rest of the proof after that is clear .
 
Last edited by a moderator:
Physics news on Phys.org
Proof.png
I'm sorry. Here you go.
 
It follows from the basic fact that, for any two numbers, u and v, [itex]|u- v|\le |u|+ |v|[/itex].

Here, [itex]u= f(x+ h)- f(x)- A_1h[/itex] and [itex]v= f(x+ h)- f(x)- A_2h[/itex].

[itex]u- v= A_2h- A_1h= (A_2- A_1)h= Bh[/itex] so [itex]|u- v|= |Bh|[/itex]
Of course, |u|= |f(x+ h)- f(x)- A_1h| and |v|= |f(x+ h)- f(x)- A_2h| so that [itex]|u- v|\le |u|+ |v|[/itex] becomes
[itex]|Bh|\le |f(x+ h)- f(x)- A_1h|+ |f(x+ h)- f(x)- A_2h|[/itex]
 
[tex]|B\mathbf{h}| = |A_2\mathbf{h} - A_1\mathbf{h}| = |\mathbf{f}(\mathbf{x} + \mathbf{h}) - \mathbf{f}(\mathbf{x}) - A_1\mathbf{h} - \mathbf{f}(\mathbf{x} + \mathbf{h}) +\mathbf{f}(\mathbf{x}) +A_2\mathbf{h}| \leq |\mathbf{f}(\mathbf{x} + \mathbf{h}) - \mathbf{f}(\mathbf{x}) - A_1\mathbf{h}| + |\mathbf{f}(\mathbf{x} + \mathbf{h}) -\mathbf{f}(\mathbf{x}) -A_2\mathbf{h}|[/tex]
 
Utilize ##|b-a|\leq|b|+|a|## (Note equality holds when ##b## is positive and ##a## is negative or when ##a##is positive and ##b## is negative or when either of them or both of them are 0.) with ##a=|f(x+h)-f(x)-A_1h|## and ##b=|f(x+h)-f(x)-A_2h|##
EDIT:- dang, micromass beat me to it.
 
Thanks a lot for answers.
 
a function s is "little oh" if the limit of |s(x)|/|x| is zero as x-->0. then the derivative at a of a function f is a linear function L such that (f(a+x) -f(a) - L(x)) is little oh as a function of x. so just prove that the only little oh and linear function is zero. that does it by subtraction.

oh yes, and it is possible the reason you are confused is that you are reading the worst book in the world for understanding. For this particular topic I suggest you try (pages 138 and 142 of) Loomis and Sternberg: Advanced Calculus, (free on Sternberg's website).

Or Spivak, Calculus on manifolds, page 16, or Dieudonne': Foundations of modern analysis page 143, or Lang, Analysis I, pages 302-303. or Fleming: Functions of several variables (corollary of) Prop. 12, page 156.

Best to do the proof yourself as suggested above.
 
Last edited: