Why Is the Mechanical Energy of a Satellite Negative?

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SUMMARY

The mechanical energy of an artificial satellite in uniform circular motion is expressed as Em = Ep + Ek, where the total mechanical energy is calculated to be -mgR/4. This negative value arises because the potential energy is defined as zero at an infinite distance, leading to a decrease in potential energy as the satellite moves closer to Earth. The kinetic energy increases as the satellite falls inward, resulting in a conservation of total energy, which is why the mechanical energy is negative.

PREREQUISITES
  • Understanding of gravitational force and its formula: GmM / r²
  • Knowledge of uniform circular motion principles
  • Familiarity with kinetic and potential energy concepts
  • Basic grasp of energy conservation in physics
NEXT STEPS
  • Study gravitational potential energy and its implications in orbital mechanics
  • Learn about the conservation of mechanical energy in satellite motion
  • Explore the relationship between kinetic energy and potential energy in gravitational fields
  • Investigate the effects of altitude on satellite speed and energy
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and orbital dynamics, as well as educators looking to clarify concepts related to satellite motion and energy conservation.

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Homework Statement


the gravitational force exerted on a body of mass m by the Earth is GmM / r2

1. Express the speed of an artificial satellite which carries out uniform circular motion at height R from the surface of the Earth in terms of g and R

2. express the mechanical energy of the artificial satellite of (1) in terms of g, m, and R, where m is the mass of the artificial satellite and the potential energy is assumed to be zero when the distance r is infinite.

Homework Equations


Em = Ep + Ek


The Attempt at a Solution


1. done [ans : v =√(gR/2) ]

2.
Em = Ep + Ek = 0 + 1/2 mv2 = 1/2 m (gR/2) = mgR / 4

but the answer is - mgR / 4. Why is there negative sign?


thanks
 
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It says, "assuming the potential energy is 0 when R is infinite". You assumed the potential energy was zero at the distance R. So there is a potential energy term you forgot to add in. As to why it is negative, the satellite has more potential energy when it is further away. This is clear if you think about an object at rest at infinity and falling inward. As it gains kinetic energy, it needs to lose potential energy so that total energy is conserved. So if the total energy is zero at infinity (since PE=0, and KE=0 since v=0), as it accelerates inward and KE increases positively, PE must increase negatively.
 
phyzguy said:
It says, "assuming the potential energy is 0 when R is infinite". You assumed the potential energy was zero at the distance R. So there is a potential energy term you forgot to add in. As to why it is negative, the satellite has more potential energy when it is further away. This is clear if you think about an object at rest at infinity and falling inward. As it gains kinetic energy, it needs to lose potential energy so that total energy is conserved. So if the total energy is zero at infinity (since PE=0, and KE=0 since v=0), as it accelerates inward and KE increases positively, PE must increase negatively.

Oh, you're right. Got it now. Thanks a lot :smile:
 

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