Why is the speed of water waves dependent on depth?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
2 replies · 16K views
quantum123
Messages
306
Reaction score
1
Why is the speed of water waves dependent on the depth?
 
Physics news on Phys.org
The velocity, c, of a simple sinusoidal surface water wave is described by, where L is the wavelength and d the water depth:

[tex]c = \sqrt {\frac{{gL\tanh \left( {\frac{{2\pi d}}{L}} \right)}}{{2\pi }}}[/tex]

Note that when d > L /2

[tex]\tanh \left( {\frac{{2\pi d}}{L}} \right) \approx 1[/tex]

so the velocity for deep water reduces to

[tex]c = \sqrt {\frac{{gL}}{{2\pi }}}[/tex]

and when d << L/2

[tex]\tanh \left( {\frac{{2\pi d}}{L}} \right) \approx \left( {\frac{{2\pi d}}{L}} \right)[/tex]

So the velocity becomes

[tex]c = \sqrt {gd}[/tex]

This is because the water particles are moving in (nearly) circular orbits in deep water. As the water shoals the bottom exerts a drag which elongates the orbit to an ellipse, which gets flatter and flatter with shoaling.
 
Roughly speaking, friction with the bottom slows the wave so that waves in deeper water are faster. The more precise derivation, showing that the wave speed is proportional to the square root of the depth is what studiot gives.