Why is the Time Period of a Pendulum & SHM Different?

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Homework Help Overview

The discussion revolves around the differences in the time period of a simple pendulum and a simple harmonic oscillator (SHO), specifically addressing why the pendulum's time period is independent of the mass of the bob while the SHO's time period is dependent on mass.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of mass on the time period of both systems, questioning how inertia and gravitational force interact in the context of a pendulum and an SHO.

Discussion Status

Some participants have offered considerations related to historical experiments and Newton's laws to frame the discussion, while others have provided insights into the relationship between mass, force, and acceleration in both scenarios. Multiple interpretations of the underlying physics are being explored.

Contextual Notes

There are references to specific historical experiments and principles of physics that may influence the understanding of the problem, but no consensus has been reached on the implications of these considerations.

Anoushka
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can someone please tell me why is the time period of a simple pendulum independent of the mass m of the bob while the time period of a simple harmonic oscillator is T=2∏√m/k!
pleaseeeee help .

Thankyou sooo much :)
 
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Hello Anoushka,

Welcome to Physics Forums!

Anoushka said:
can someone please tell me why is the time period of a simple pendulum independent of the mass m of the bob while the time period of a simple harmonic oscillator is T=2∏√m/k!
pleaseeeee help .

Thankyou sooo much :)
I can't give you the answer, but I will give you a couple things to consider.

//=============
// Consideration 1
//=============

It has been said that Galileo Galilei performed an experiment in which he simultaneously dropped two dense objects with unequal masses from the Leaning Tower of Pisa. Contrary to to the popular predictions of many other people, the objects hit the ground at the same time (even though one was significantly heavier than the other).

Jump forward a century or so and consider Isaac Newton's second law of motion.

[tex]\vec F = m \vec a[/tex]
Even if the mass [itex]m[/itex] is a variable in this equation, what it is that remains constant when considering objects falling due to gravity? Does [itex]\vec F[/itex] remain constant or does [itex]\vec a[/itex]?

Now it might help to repeat the same consideration, except instead of objects in perfect free fall, apply the considerations to various sized masses on a frictionless incline.

Can you see the relationship between that and an approximation to a pendulum? (Hint: assume small angles)

//=============
// Consideration 2
//=============

Now consider various sized masses attached to a particular, ideal spring. Suppose the spring also has particular compression x0 at some point in time.

Don't forget Newton's second law,
[tex]\vec F = m \vec a[/tex]
In this situation with a particular spring at a particular displacement, what is it that stays constant even if the mass changes? Does [itex]\vec F[/itex] remain constant or does [itex]\vec a[/itex]? :wink:
 
Last edited:


A pendulum is an example of a simple harmonic ocillator.

Think about this too:

When you increase the mass of the pendulum the intertia of the pendulum increases the same as the force of gravity on the pendulum. The extra force of gravity is canceled exactly by the increase in inertia. Hence the resulting acceleration is constant but for a larger mass it take more force to achieve. Exactly the extra force provided by the addition mass.
 


marty1 said:
A pendulum is an example of a simple harmonic ocillator.

Think about this too:

When you increase the mass of the pendulum the intertia of the pendulum increases the same as the force of gravity on the pendulum. The extra force of gravity is canceled exactly by the increase in inertia. Hence the resulting acceleration is constant but for a larger mass it take more force to achieve. Exactly the extra force provided by the addition mass.

Marty1 and Collinsmark thanks a lot you guys , that was really helpful! :D
 

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