Why is the work done against friction not equal to the force times distance?

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Homework Statement


the question and answers are in the attachment, I don't understand question 8b) (ii), why is the work done against friction =f x d and not 10N x d?


Homework Equations





The Attempt at a Solution

 
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For some reason, I cannot view those attachments. Can you describe the problem?
eureka_beyond said:
why is the work done against friction =f x d and not 10N x d?
The obvious question is: What does the friction force equal?
 
okay, the question goes like this:
on a rough horizontal Ground, a 3 kg block at rest is moved be a Force of 10N. The acceleration of the block is 2ms-2.
if the force ceases to act after 4 seconds,
what 's the further distance traveled by the block before it comes to rest?
 
eureka_beyond said:
if the force ceases to act after 4 seconds,
That means the 10 N force is no longer applied.
what 's the further distance traveled by the block before it comes to rest?
What's the only force acting to slow down the block?
 
eureka_beyond said:
that's got to be the friction, right?
Yes. Now use the given information to figure out the friction force. (Hint: Newton's 2nd law.)
 
by Newton's 2nd law
F=ma
Let the friction be f
10-f=3(2)
f=4N
 
eureka_beyond said:
by Newton's 2nd law
F=ma
Let the friction be f
10-f=3(2)
f=4N
Good!
 
yay! thanks a million. but there's another thing, how do I get the further distance traveled by the block before it comes to rest?
 
eureka_beyond said:
yay! thanks a million. but there's another thing, how do I get the further distance traveled by the block before it comes to rest?
Several ways:
(1) You can find the acceleration and use kinematics. (First figure out how fast the block is moving at the end of 4 seconds.)
(2) You can set the work done by friction equal to the change in kinetic energy.
 
ah, I see. The book must have been using the second way you describe, I get it now, thanks a lot.