Why is the zenith angle distribution of the muons cos2(x) ?

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Discussion Overview

The discussion centers around the observed zenith angle distribution of cosmic ray muons, which follows a cos²(θ) pattern, where θ represents the angle of incidence. Participants explore potential explanations for this empirical observation, considering both theoretical and experimental perspectives.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes that the flux distribution of cosmic ray muons follows a cos²(θ) pattern but lacks a deeper physical explanation in the literature.
  • Another participant suggests that the distribution might be a simple function that approximates the real distribution without a solid physical basis.
  • A different viewpoint emphasizes the geometry of the Earth's atmosphere, arguing that the path length for muons is minimized at θ=0, leading to a cos-like distribution.
  • This participant also references the Bethe-Bloch formula, suggesting that energy loss per unit length affects the likelihood of detecting muons at small angles compared to larger angles.
  • Another participant points out that if cosmic rays were uniform and isotropic, a distribution proportional to 1/cos(θ) would be expected, but the presence of the atmosphere alters this expectation.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the underlying reasons for the cos²(θ) distribution, with no consensus on a definitive explanation. Multiple competing views are presented, and the discussion remains unresolved.

Contextual Notes

Participants acknowledge limitations in deriving the distribution from first principles, noting the dependence on atmospheric conditions and the geometry of the Earth.

phys_student1
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Hello,

Empirically, the flux distribution of cosmic ray muons follow cos^2(θ) where θ is angle of incidence. Looking up the papers, I did not find any clue as to why is this the case. All sources simply consider this an experimental fact.

Is their any real explanation for this?
 
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That is a common question and I never saw a good answer. It is probably just some function which is not so far away from the real distribution, without a deeper physical argument behind it.
 
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First of all consider that the Earth's atmosphere is a perfect sphere.
The path length for θ=0 is the minimum possible.
Also note that there no chance to detect a muon for θ=π/2(for this specific angle the muon would have to travel along the Earth's crust, it would collide and interact with the crust's atoms with a very high probability).

Those arguments state that we need a cos-like distribution.

The next step is to think that the muon obeys the Bethe-Bloch formula. In simple words the energy loss per unit length, is something like 1/β^2...

This implies that it is very much likely to observe a muon for small θ(where the path length is minimum) rather that large θ, in a non-linear way.

If you also put in mind that the Earth's atmosphere isn't a perfect sphere, but it's a "3D ellipsoidal", you are again moving away from linearity.

I believe that Andersson has done some "fitting" on experimental data of cosmic ray flux, which proves the cos^2θ distribution.

So it is an experimental model, as far as I know.
 
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This is an approximation, and as such, you won't be able to derive it.

If cosmic rays were uniform and isotropic, you'd expect a distribution that goes more like 1/cos(theta), because there's not a lot of area with a small zenith angle compared to a large one. However, as atha points out, we have an atmosphere, so cosmic rays from the horizon are unlikely to make it to us.
 
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Thanks all. Yes I also looked too much in the literature without finding any clue, all state is as empirical formula or experimental fact. Thanks for your responses.
 

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