MHB Why is this polynomial separable?

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The discussion revolves around the concept of separability in polynomials, particularly focusing on the polynomial f(x) = (x^2-2)^2(x^2+3). It is established that a polynomial is separable if all its irreducible factors are separable, which is confirmed by the irreducible factors of f. There is some confusion regarding the roots of the factors, particularly with multiplicities, leading to a deeper exploration of inseparable polynomials. An example of an inseparable polynomial is discussed, specifically x^3-2 in F_3[x], highlighting the nuances of irreducibility and separability definitions across different sources. The conversation concludes with a recognition of differing definitions of irreducibility and separability in various mathematical texts.
mathmari
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Hey! :o

In my notes there is the following:

Let $F$ be a field. The irresducible $f\in F[x]$ is separable, if all the roots are different.
A non-constant polynomial $f\in K[x]$ is separable, if all the irreducible factors are separable.

Example:
$f(x)=(x^2-2)^2(x^2+3)\in \mathbb{Q}[x]$.
The irreducible factors are:
  • $x^2-2$ $\rightarrow$ Roots : $\pm 2$ different
  • $x^2+3$ $\rightarrow$ Roots : $\pm i\sqrt{3}$ different
So, $f$ is separable. I haven't understood why $f$ is separable. Since we have the factor $(x^2-2)^2$ aren't the roots $\pm 2$ of multiplicity $2$ ? (Wondering)
 
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mathmari said:
Hey! :o

In my notes there is the following:

Let $F$ be a field. The irresducible $f\in F[x]$ is separable, if all the roots are different.
A non-constant polynomial $f\in K[x]$ is separable, if all the irreducible factors are separable.

Example:
$f(x)=(x^2-2)^2(x^2+3)\in \mathbb{Q}[x]$.
The irreducible factors are:
  • $x^2-2$ $\rightarrow$ Roots : $\pm 2$ different
  • $x^2+3$ $\rightarrow$ Roots : $\pm i\sqrt{3}$ different
So, $f$ is separable. I haven't understood why $f$ is separable. Since we have the factor $(x^2-2)^2$ aren't the roots $\pm 2$ of multiplicity $2$ ? (Wondering)

Hey mathmari!

Aren't the roots $\pm \sqrt 2$? (Wondering)

And isn't $f(x)$ reducible? That would mean that the first statement doesn't apply.
I think we should apply the second statement first. (Thinking)
 
I like Serena said:
Aren't the roots $\pm \sqrt 2$? (Wondering)

Ah yes... (Blush)
I like Serena said:
And isn't $f(x)$ reducible? That would mean that the first statement doesn't apply.
I think we should apply the second statement first. (Thinking)

Yes, we apply the second statement first. The irreducible factors $x^2-2$ and $x^2+3$, right? (Wondering)
 
So, an inseparable polynomial is for example $f(x)=(x^2-4)^2(x^3-8)$, where the irreducible factors are $x^2-4$ and $x^3-8$, and the roots are $\pm 2$ and $2$ ? (Wondering)
 
mathmari said:
Yes, we apply the second statement first. The irreducible factors $x^2-2$ and $x^2+3$, right?
Yes. That's what your example states as well.

mathmari said:
So, an inseparable polynomial is for example $f(x)=(x^2-4)^2(x^3-8)$, where the irreducible factors are $x^2-4$ and $x^3-8$, and the roots are $\pm 2$ and $2$?

Can't we reduce $x^3-8$ to $(x-2)(x^2+2x+4)$? (Wondering)
 
I like Serena said:
Can't we reduce $x^3-8$ to $(x-2)(x^2+2x+4)$? (Wondering)

Ah, so it is again separable, right? (Wondering)

Could you give me an example of an inseparable polynomial? (Wondering)
 
mathmari said:
Could you give me an example of an inseparable polynomial? (Wondering)

How about $x^3-2$ in $F_3[x]$? (Wondering)
 
I like Serena said:
How about $x^3-2$ in $F_3[x]$? (Wondering)

I saw now in my notes the following proposition:
If $F$ is finite, then each non-constant $f\in F[x]$ is separable.

We have that $F_3$ is finite, right? Therefore, $x^3-2$ is separable, isn't it? (Wondering)
 
mathmari said:
I saw now in my notes the following proposition:
If $F$ is finite, then each non-constant $f\in F[x]$ is separable.

We have that $F_3$ is finite, right? Therefore, $x^3-2$ is separable, isn't it? (Wondering)

Well... $x^3-2$ is irreducible, but we also have $x^3-2=(x+1)^3$ in $F_3[x]$, so $2$ is a triple root.
If that doesn't mean it's inseparable, I wouldn't know what is.

Do your notes give an example of an inseparable polynomial?
Or do you have a proof for that proposition? (Wondering)
 
  • #10
I like Serena said:
Well... $x^3-2$ is irreducible, but we also have $x^3-2=(x+1)^3$ in $F_3[x]$, so $2$ is a triple root.
If that doesn't mean it's inseparable, I wouldn't know what is.

Do your notes give an example of an inseparable polynomial?
Or do you have a proof for that proposition? (Wondering)

In this book the chapter 3.4 (p.11) is about separability. This proposition is the 3.4.5 and the only example of an inseparable polynomial that I found is the one that is at 3.4.8.

(Thinking)
 
  • #11
mathmari said:
In this book the chapter 3.4 (p.11) is about separability. This proposition is the 3.4.5 and the only example of an inseparable polynomial that I found is the one that is at 3.4.8.

(Thinking)

This book gives example 1.2 with $x^3-2$ in $F_3[x]$ as an inseparable polynomial.
But its definition of inseparable seems to be different from your definition.
Btw, wiki seems to give a different definition as well. (Thinking)

I can see that your book considers $x^3-2$ reducible, since it is reducible over $F_3$. It seems that my book reference considers $x^3-2$ irreducible, but to be honest I'm not sure why. Wiki's definition of irreducible seems to imply that it's reducible.
 

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