Why Is Understanding Capacitor Equations Crucial?

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Homework Help Overview

The discussion revolves around understanding capacitor equations, specifically in the context of a plate capacitor with circular plates. Participants are exploring the relationship between capacitance, charge, and voltage, particularly when a dielectric material, water, is involved.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express confusion regarding the equations related to capacitance and the factors that influence it, such as plate area and dielectric constant. There are attempts to clarify how these elements interact to determine voltage and charge.

Discussion Status

Some participants have begun to identify relevant equations and concepts, while others are still grappling with the material. There is an indication that further research and clarification may be helping to advance understanding, but no consensus has been reached on the overall problem.

Contextual Notes

Participants mention difficulty in articulating their questions in English and express uncertainty about how various concepts connect. There is a specific focus on the parameters of the capacitor, including dimensions and the dielectric material used.

Zeymare
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Homework Statement
There is a plate capacitor with round plates which have a diamter ov 0.3 meters and a plate distance of 0.00001 meters (or 0.01 mm). The Gap between both plates is filled with water. How high does the voltage on the capacitor have to be, to be able to save the charge of 0.001267 C (1.267 mC)? (one plate is positive, the other negative)
Relevant Equations
Capacity C = Charge Q/Voltage U
i didnt understand anything really, i read it a few times but i don't get it
 
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Its actually relly hard to put the question in english. But we need to use multiple things to be able to calculate that, for example the area of a Circle and the electric field constant. but i just don't know how everything ties together.
 
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Zeymare said:
Homework Statement:: There is a plate capacitor with round plates which have a diamter ov 0.3 meters and a plate distance of 0.00001 meters (or 0.01 mm). The Gap between both plates is filled with water. How high does the voltage on the capacitor have to be, to be able to save the charge of 0.001267 C (1.267 mC)? (one plate is positive, the other negative)
Relevant Equations:: Capacity C = Charge Q/Voltage U

i didnt understand anything really, i read it a few times but i don't get it
Welcome to the PF. :smile:

Can you show us the Relevant Equation for the Capacitance of a parallel plate capacitor in terms of the plate area and separation, and the value of the dielectric constant ##\epsilon## of the material filling the space between the plates?

And then what is the equation for the charge stored on a capacitor, in terms of the capacitance and the applied voltage? :smile:
 
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berkeman said:
Welcome to the PF. :smile:

Can you show us the Relevant Equation for the Capacitance of a parallel plate capacitor in terms of the plate area and separation, and the value of the dielectric constant ##\epsilon## of the material filling the space between the plates?

And then what is the equation for the charge stored on a capacitor, in terms of the capacitance and the applied voltage? :smile:
I am sorry for the late answer but i think i figured it out now. After you mentioned the equations, i researvhed a bit on google (because i didnt understand them in my book) and realized that i understood something completetly the wrong way and that's why i couldn't continue...so thank you
 
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