Why Is Understanding Capacitor Equations Crucial?

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Zeymare
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Homework Statement
There is a plate capacitor with round plates which have a diamter ov 0.3 meters and a plate distance of 0.00001 meters (or 0.01 mm). The Gap between both plates is filled with water. How high does the voltage on the capacitor have to be, to be able to save the charge of 0.001267 C (1.267 mC)? (one plate is positive, the other negative)
Relevant Equations
Capacity C = Charge Q/Voltage U
i didnt understand anything really, i read it a few times but i don't get it
 
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Its actually relly hard to put the question in english. But we need to use multiple things to be able to calculate that, for example the area of a Circle and the electric field constant. but i just don't know how everything ties together.
 
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Zeymare said:
Homework Statement:: There is a plate capacitor with round plates which have a diamter ov 0.3 meters and a plate distance of 0.00001 meters (or 0.01 mm). The Gap between both plates is filled with water. How high does the voltage on the capacitor have to be, to be able to save the charge of 0.001267 C (1.267 mC)? (one plate is positive, the other negative)
Relevant Equations:: Capacity C = Charge Q/Voltage U

i didnt understand anything really, i read it a few times but i don't get it
Welcome to the PF. :smile:

Can you show us the Relevant Equation for the Capacitance of a parallel plate capacitor in terms of the plate area and separation, and the value of the dielectric constant ##\epsilon## of the material filling the space between the plates?

And then what is the equation for the charge stored on a capacitor, in terms of the capacitance and the applied voltage? :smile:
 
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berkeman said:
Welcome to the PF. :smile:

Can you show us the Relevant Equation for the Capacitance of a parallel plate capacitor in terms of the plate area and separation, and the value of the dielectric constant ##\epsilon## of the material filling the space between the plates?

And then what is the equation for the charge stored on a capacitor, in terms of the capacitance and the applied voltage? :smile:
I am sorry for the late answer but i think i figured it out now. After you mentioned the equations, i researvhed a bit on google (because i didnt understand them in my book) and realized that i understood something completetly the wrong way and that's why i couldn't continue...so thank you
 
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