- #1

- 62

- 0

**|r|**u

^{2}=r.r=^{i}

**e**

_{i}.u

^{j}

**e**

_{j}

Why are i and j different because we are dotting the same vector?

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- A
- Thread starter LSMOG
- Start date

- #1

- 62

- 0

Why are i and j different because we are dotting the same vector?

- #2

- 16,933

- 6,739

$$

\vec u \cdot \vec u = (u^1 \vec e_1 + u^2 \vec e_2 + u^3\vec e_3) \cdot (u^1 \vec e_1 + u^2 \vec e_2 + u^3\vec e_3) = (u^i \vec e_i) \cdot (u^j \vec e_j).

$$

Consider what this would have been if you had used the same index and still summed over it

$$

u^1 \vec e_1 \cdot u^1 \vec e_1 + u^2 \vec e_2 \cdot u^2 \vec e_2 + u^2 \vec e_2 \cdot u^2 \vec e_2.

$$

You might say that you can tell the sums apart anyway but my experience after teaching relativity for several years is that you really cannot and that you really need to separate the sums using different indices. One of the more common errors students do is to use the same summation index for different sums and then they forget which belonged where and happily (until they get their test score back) sum the wrong terms together.

- #3

- 62

- 0

Thanks sir

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