Why Is Work Equal to Zero When Forces Are Perpendicular?

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Homework Help Overview

The discussion revolves around the concept of work in physics, particularly why work is considered to be zero when forces are perpendicular to the direction of motion. The subject area is primarily focused on mechanics and the work-energy theorem.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express confusion regarding the relationship between the normal force and the direction of motion, particularly questioning how a force acting perpendicular can result in zero work. There are references to the work-energy theorem and its implications for kinetic energy.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the concept of work and the role of the normal force. Some have suggested looking into the work-energy theorem for further understanding, while others are grappling with the implications of forces acting at right angles to motion.

Contextual Notes

Participants are working within the constraints of a homework assignment, indicating a need for clear explanations without advanced assumptions. There is a noted difficulty in understanding the basic principles involved.

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Homework Statement



See the picture attached please. I need help understanding the concept of why work is = 0. I don't understand it's explanation. Please bare with me for the silly questions.


Homework Equations



W=Kf-Ki

W=Fdcosθ

The Attempt at a Solution



I can't understand why It mentions the normal force acting perpendicular if its being pushed to the left not up.
 

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xtrubambinoxpr said:
See the picture attached please. I need help understanding the concept of why work is = 0.
The total work is zero, since the kinetic energy doesn't change. Look up the work-energy theorem.

I can't understand why It mentions the normal force acting perpendicular if its being pushed to the left not up.
The object is moving parallel to the the ramp, but the normal force acts perpendicular to it. So does the normal force do any work in this case?
 
Doc Al said:
The total work is zero, since the kinetic energy doesn't change. Look up the work-energy theorem.


The object is moving parallel to the the ramp, but the normal force acts perpendicular to it. So does the normal force do any work in this case?


You will have to dumb it down a good amount for me =/
 
xtrubambinoxpr said:
I can't understand why It mentions the normal force acting perpendicular if its being pushed to the left not up.

If a particle moves on a frictionless rigid surface, due to the fact that this surface constrains the motion of the particle, we have an additional force acting (locally) perpendicularly to the surface.
 

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