Why isn't the imaginary component j included in the complex vector equation?

Click For Summary
SUMMARY

The discussion centers on the absence of the imaginary component "j" in the complex vector equation \(\hat{v}(t) = \cos(\omega t)\hat{x} + \sin(\omega t)\hat{y}\). Participants clarify that the notation mixes real and complex representations, suggesting that if \(\hat{x}\) represents 1 and \(\hat{y}\) represents "j", then \(\hat{v}(t)\) can indeed be expressed as a complex number. The exponential function \(e^{it}\) is identified as a valid representation of the vector in complex form. The need for clarity in notation is emphasized, particularly in educational contexts.

PREREQUISITES
  • Understanding of complex numbers and their representation
  • Familiarity with vector notation in physics and mathematics
  • Knowledge of trigonometric functions and their relationship to complex exponentials
  • Basic concepts of isomorphism between R² and C
NEXT STEPS
  • Research the relationship between complex numbers and 2D vectors
  • Study the properties of the exponential function \(e^{it}\) in complex analysis
  • Learn about the isomorphism between R² and C in mathematical contexts
  • Explore advanced vector notation and its applications in physics
USEFUL FOR

Students of mathematics and physics, educators clarifying complex vector concepts, and anyone interested in the relationship between complex numbers and vector representations.

jeff1evesque
Messages
312
Reaction score
0
Problem/Statement
The complex vector, \hat{v}(t) = cos(\omega t)\hat{x} + sin(\omega t)\hat{y} is the unit vector \hat{v}(t) expressed in instantaneous form.

Question
What I am wondering is, why is there no imaginary component "j" in say the sin component for the equation above?

Can we express a general notation for complex vectors as,
\hat{v}(t) = [cos(\omega t) + sin(\omega t)]\hat{x}] + [cos(\omega t) + sin(\omega t)]\hat{y}]? Shouldn't that be the notation for the instantaneous form also?Thanks,Jeff
 
Last edited:
Physics news on Phys.org
Weird. You'd have to consult the source of the question (either your book or your professor or whatnot).

With the hats over the x and y, it almost looks like they are mixing R^2 and C. The two are, in fact, isomorphic, and anything you can say about complex numbers translates simply to a statement about vectors in a 2D plane.

If it were me, I'd make the assumption that they meant x = 1 and y = j. That way, v(t) is a complex number. (In fact, v would be the exponential function, e^{it}).
 
Tac-Tics said:
Weird. You'd have to consult the source of the question (either your book or your professor or whatnot).

With the hats over the x and y, it almost looks like they are mixing R^2 and C. The two are, in fact, isomorphic, and anything you can say about complex numbers translates simply to a statement about vectors in a 2D plane.

If it were me, I'd make the assumption that they meant x = 1 and y = j. That way, v(t) is a complex number. (In fact, v would be the exponential function, e^{it}).

Yea, I'm not sure. I think I will ask the teacher tomorrow. Oh I think I meant the following (as well),

Can we express a general notation for complex vectors as,
\hat{v}(t) = [[cos(\omega t) + sin(\omega t)]\hat{x} + j[cos(\omega t) + sin(\omega t)]\hat{y}]? Shouldn't that be the notation for the instantaneous form also?
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
Replies
5
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K