Undergrad Troubleshooting a Derivation: Why μ*ε=1/c^2?

Click For Summary
SUMMARY

The discussion centers on the derivation of the relationship μ*ε=1/c², which is crucial in understanding electromagnetic wave propagation. The user references a video that explains the wave equation, specifically at the 10:20 mark, where the equation v²=ω²/k² is presented. It is established that in this context, v² is equivalent to 1/(μ₀ε₀), linking the speed of light to the permeability (μ₀) and permittivity (ε₀) of free space. This relationship is fundamental in electromagnetism and wave theory.

PREREQUISITES
  • Understanding of electromagnetic theory
  • Familiarity with wave equations
  • Knowledge of the constants μ₀ (permeability) and ε₀ (permittivity)
  • Basic calculus and algebra for manipulating equations
NEXT STEPS
  • Study the derivation of the wave equation in detail
  • Learn about the physical significance of μ₀ and ε₀ in electromagnetism
  • Explore the implications of the speed of light in various media
  • Investigate the relationship between wave speed, frequency, and wavelength
USEFUL FOR

Students and professionals in physics, particularly those focused on electromagnetism and wave mechanics, as well as educators seeking to clarify these concepts for learners.

snate
Messages
7
Reaction score
1
I've been following the derivations in the following video up until that point. I don't quite understand why does it imply that μ*ε=1/c^2. Thanks.

ph.jpg
 
Physics news on Phys.org
Check out the wave equation earlier on in the video (10:20) . ##v^2=\omega^2/k^2 ## and ##{1\over \mu_0\varepsilon_0}## takes that place, so ##v^2 = {1\over \mu_0\varepsilon_0}## .
 
  • Like
Likes snate

Similar threads

  • · Replies 8 ·
Replies
8
Views
10K
  • · Replies 34 ·
2
Replies
34
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K