Why Might Ay Be Bigger Than Ax in a Triangle?

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SUMMARY

The discussion centers on the mechanics of forces in a triangle, specifically addressing why the vertical component (Ay) can exceed the horizontal component (Ax) despite the given dimensions of the triangle. The user questions the validity of their equation for the x dimension, suggesting that the angle of force A influences its components. It is established that A must balance other forces, which are predominantly vertical, leading to a greater vertical force component.

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Homework Statement





The attached question(question 1) is in finnish, but you'll understand it no problem!;) The answers are given at the end of the text part of the question.

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The Attempt at a Solution


Firstly, I'm wondering how can Ay be bigger than Ax even though the X side of the little triangle at the left end of the boom is 4 and Y is 3?

Secondly, why can't I write the equation for the x dimension as follows: [tex]\sum[/tex]F= -400sin15+0,8A=0

 

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A is not a normal*** force. If it were, we'd have

Ax = 3/5 A

A must act to balance the other forces that are present. Since the other forces are close to being vertical, A is closer to vertical than to horizontal.


*** "normal" means the force is perpendicular to the surface
 

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