EMF in bigger loops kept on both sides of a small loop

[Pushoam]

Homework Statement

Modification: Take two big loops kept on both sides of the small loop at a distance a from the corresponding end of the small loop.

Homework Equations

The Attempt at a Solution

The flux through the bigger loop is equal to the flux through the smaller loop, provided that the current through the bigger loop is I.
Let's say that the current I is in the left bigger loop.
Then, the flux through the small loop = $\frac { \mu_0 I a \ln 2 }{2 \pi}$
So, the emf is ξ = - $\frac { \mu_0 ka \ln 2 }{2 \pi}$
Is this correct so far?

 

[Tanishq Nandan]

Modification: Take two big loops kept on both sides of the small loop at a distance a from the corresponding end of the small loop

What was the need for all this??
This seems to be a question related to mutual inductance.
You should know that emf induced will be equal to M×di/dt
You have been given di/dt
You just need to find M.
For doing that,you may use the formula M=(flux in anyone loop caused due to current in another loop)/that current
How to apply this formula..well,that's where the trick usually lies in these questions..

 

[Pushoam]

I have got the answer.
Thanks