Why Might Option B Be Correct in This Collision Problem?

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Homework Help Overview

The discussion revolves around a collision problem involving forces acting on a table. Participants are attempting to understand the implications of various forces, including the weight of the table, in determining the correct answer to the problem.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are examining the role of the table's weight in the overall force calculations. There are attempts to clarify how different forces contribute to the total force acting on the table and its legs.

Discussion Status

Some participants have provided insights regarding the forces involved, including the weight of the table and how it affects the calculations. There is ongoing exploration of the implications of these forces, but no consensus has been reached on the correctness of the original poster's assumptions or calculations.

Contextual Notes

Participants are working under the constraints of the problem as presented, which includes specific forces and conditions related to the collision scenario. The original poster expresses uncertainty about the correctness of their answer compared to the provided options.

coldblood
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Hi friends,
I have an issue in solving a Collision Problem.
Please Help me in solving this.
Thank you all in advance.

The problem is as:

https://fbcdn-sphotos-c-a.akamaihd.net/hphotos-ak-frc3/q71/s720x720/1384332_1432382970322142_101322866_n.jpg


Attempt:

https://fbcdn-sphotos-d-a.akamaihd.net/hphotos-ak-ash3/q81/s720x720/994348_1432381503655622_646459501_n.jpg

So friends according to me the answer should be option (A) but according to question option, (B) is correct. Please try to help me in this.
I will appreciate the help.
 
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You didn't count with the weight of the table.

ehild
 
ehild said:
You didn't count with the weight of the table.

ehild

Ok, well that 0.5N.will act in the downward direction on the table. And weight of the table will be 0.2 x 10 = 2N.
Hence the total force would be 7 N. downward. On leg reaction would be 7/4 = 1.75N.
Is it correct?
 
coldblood said:
Ok, well that 0.5N.will act in the downward direction on the table. And weight of the table will be 0.2 x 10 = 2N.
Hence the total force would be 7 N. downward. On leg reaction would be 7/4 = 1.75N.
Is it correct?

2N force acts on the whole table because of the collisions. See your own solution in the first post.

ehild
 
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