Acceleration of centre of mass problem

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SUMMARY

The discussion centers on solving an "Acceleration of center of mass" problem, where the user initially believes the correct answer is option (b), but the question states it is option (a). The user concludes that when converting the answer to vector form, the direction indicated by the negative sign will not be shown, leading to the correct interpretation aligning with option (a). The key takeaway is the importance of vector direction in determining the correct answer in physics problems.

PREREQUISITES
  • Understanding of vector representation in physics
  • Knowledge of acceleration concepts
  • Familiarity with center of mass calculations
  • Basic grasp of sign conventions in physics
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  • Study vector addition and subtraction in physics
  • Learn about center of mass calculations in multi-body systems
  • Explore the implications of sign conventions in physics problems
  • Review acceleration concepts and their applications in mechanics
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Students studying physics, educators teaching mechanics, and anyone interested in mastering vector analysis and center of mass problems.

coldblood
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Hi friends,
I have an issue in solving a Acceleration of center of mass problem.
Please Help me in solving this.
Thank you all in advance.

The problem is as:

https://fbcdn-sphotos-a-a.akamaihd.net/hphotos-ak-prn2/q71/s720x720/1395961_1432382973655475_777941089_n.jpg


Attempt:

https://fbcdn-sphotos-d-a.akamaihd.net/hphotos-ak-ash4/q82/s720x720/1381887_1432380636989042_263502974_n.jpg

Friends according to me the answer should be Option (b) but question says the answer is option (a).Please try to help me in this.
I will appreciate the help.
 
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When you will convert your answer to vector form, the answer would match option (a). Because the vectors include the direction, so minus sign will not be shown. Assuming positive direction to be downwards, then ##\vec{R}=-R##
 
NihalSh said:
When you will convert your answer to vector form, the answer would match option (a). Because the vectors include the direction, so minus sign will not be shown. Assuming positive direction to be downwards, then ##\vec{R}=-R##

Thanks NihalSh, I got that.
Thank for the help.
 

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