Why semiconductor in Hall effect sensor?

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Semiconductors are preferred over resistors in Hall effect sensors because resistors limit current flow and consume more power, which is undesirable for sensor operation. Semiconductors allow for better control and efficiency, enhancing the sensor's performance. The Hall effect relies on the movement of charge carriers, with P-type semiconductors utilizing holes and N-type using electrons, potentially enabling advanced differential analysis. This combination of charge carriers contributes to the sensor's sensitivity and accuracy. Overall, the use of semiconductors significantly improves the functionality of Hall effect sensors compared to basic resistors.
jaydnul
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Why is a slab of semiconductor used instead of just a basic resistor. The charge would be pushed to either side by the magnetic field in the same way, would it not?
 
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That's a good question. I would imagine that resistors are not used because they inherently limit the flow of current, which is not what you want with a hall effect sensor since it relies on current to operate (not to mention the fact that resistors typically consume a lot of power compared to a semiconductor device). A quick search only tells me that semiconductor devices are used because they offer superior operation, but I haven't been able to find out why yet. I'll let you know if I find out anything else.
 
Another possible reason (or perhaps part of the same reason) is that the charge carriers in P type semiconductors are holes (positive charges) instead of electrons. The Hall effect causes the electrons to migrate to one side of a conductor, and the holes to the other as I recall. Thus we could in theory use an N type for the electrons and a P type for the holes and maybe do some clever differential analysis. This is only speculation though.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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