Why T sin θ gives radial acceleration in a conical pendulum

[mc8569]

Consider a conical pendulum with a weight on it and that makes some angle with the vertical. I am told to find the radial acceleration of the weight and someone showed me how it is solved but I don't understand why:

I am told to set

Tsin@ = m(ar) *ar = radial acceleration
ar = (Tsin@)/m

I was wondering why it would be T*SIN* instead of T*COS*? Tcos@ would give you the force that is parallel with radial acceleration, Tsin@ gives you a force that is perpendicular to the radial acceleration... Please help me! I don't understand this - only should take a few seconds. Thanks! XP

 

[mc8569]

AHHHH OHHH NEVERMIND! Sorry... *CONICAL* pendulum, lol I was thinking of a regular, 2-D pendulum. I would delete this if I could, but I can't =\ But no need to respond anyone! So silly!