Why the second quantization Hamiltonian works?

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SUMMARY

The discussion centers on the application of single-particle and two-particle Hamiltonians in quantum mechanics, specifically in the context of non-interacting and interacting multi-particle systems. It is established that a single-particle Hamiltonian can be effectively utilized in N-particle space due to its representation in Fock space, which encompasses all N-particle configurations. Additionally, the two-particle Hamiltonian can be directly applied to multi-particle cases involving pair interactions, highlighting the underlying formalism that allows for this versatility in quantum mechanics.

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  • Understanding of quantum mechanics principles
  • Familiarity with Hamiltonian operators
  • Knowledge of Fock space and its properties
  • Concept of annihilation and creation operators
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Physicists, quantum mechanics students, and researchers interested in the theoretical foundations of quantum systems and the application of Hamiltonians in multi-particle scenarios.

MichPod
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I am puzzled by the fact that a "single-particle" Hamiltonian (in the annihilation and creation operator form) may be used for a multi-particle case (non-interacting particles) or that (only) a "two-particle" Hamiltonian (in the annihilation and creation operator form) may be used for a multi-particle case of many (pair-) interacting particles.

I'd like to learn more what ideas stay behind this i.e. why a two-particle Hamiltonian may be used so directly for a multiple-particle case. Is it just a coincidence, a trick, or there is some reason/theory/formalism behind this?
 
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A single-particle Hamiltonian has a representation on ##N##-particle space for all values of ##N##. The annihilation and creation operators act on the corresponding Fock space, which is the direct sum of all ##N##-particle spaces. The single-particle Hamiltonian has a representation there, too.
 
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