Why use a laurent series in complex analysis?

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Laurent series are essential in complex analysis for approximating meromorphic functions, which have poles, unlike Taylor series that only handle analytic functions. They generalize Taylor series by incorporating negative powers, allowing for the representation of functions that exhibit singular behavior. This capability is crucial for analyzing rational functions and other expressions involving holomorphic functions. The algebraic structure of Laurent series also parallels that of rational numbers to integers, highlighting their importance in complex function theory. Ultimately, Laurent series provide a broader framework for understanding complex functions that Taylor series cannot address.
ENgez
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In complex analysis, what exactly is the purpuse of the luarent series, i mean, i know that it apporximates the function like a taylor series, an if the function is analytic in the whole domain it simplifies into a taylor series. But i fail to see its purpose - what does it do that the taylor series can't?
 
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Hello!

In complex analysis, we're often interested in functions that are not holomorphic/analytic, but are meromorphic: http://en.wikipedia.org/wiki/Meromorphic_function.

In this case, Laurent series are a generalization of Taylor series, since now we can approximate functions that have poles using a series. Take a look at this article: http://en.wikipedia.org/wiki/Residue_(complex_analysis).

Also, just like power series, the collection of Laurent series has a rich algebraic structure as well.
 
why do we want to divide? the set of all quotients of taylor series are exactly the laurent series. i.e. laurent series are to taylor series as rational numbers are to integers.
 
ENgez said:
But i fail to see its purpose - what does it do that the taylor series can't?
well, it has negative powers. E.g. you might want to consider rational functions, or e^/z/z, or e^(1/z), or ... just any quotient of holomorphic functions, as mathwonk says.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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